【发布时间】:2021-09-30 23:20:18
【问题描述】:
我有一个非常基本的问题,我创建了一个 AWS Glue 作业,我需要在从 dynamodb 表中提取数据时创建一个过滤器。我只需要使用名为“时间”的字段提取前一天的数据。
import sys
from awsglue.transforms import *
from awsglue.utils import getResolvedOptions
from pyspark.context import SparkContext
from awsglue.context import GlueContext
from awsglue.job import Job
import re
args = getResolvedOptions(sys.argv, ['JOB_NAME'])
sc = SparkContext()
glueContext = GlueContext(sc)
spark = glueContext.spark_session
job = Job(glueContext)
job.init(args['JOB_NAME'], args)
DataSource0 = glueContext.create_dynamic_frame.from_catalog(database = "sampledb", table_name = "tablex", transformation_ctx = "DataSource0")
Transform1 = ApplyMapping.apply(frame = DataSource0, mappings = [("allresults.paymentCapabilityResult.paymentCapabilityCheckResult", "boolean", "allresults.paymentCapabilityResult.paymentCapabilityCheckResult", "boolean"), ("time", "string", "time", "timestamp")], transformation_ctx = "Transform1")
DataSink0 = glueContext.write_dynamic_frame.from_options(frame = Transform1, connection_type = "s3", format = "json", connection_options = {"path": "s3://xxxxx/output/", "partitionKeys": []}, transformation_ctx = "DataSink0")
job.commit()
【问题讨论】:
-
时间是怎样的?
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dynamodb 时间字段如下所示: 时间字符串:Thu Sep 03 2020 01:43:52 GMT+000 (Coordinated Universal Time) 实际上该字段被定义为字符串,所以我猜首先我需要转换为日期/时间,然后进行过滤,对吗?
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是的,您需要先将其解析为时间戳。
标签: python amazon-s3 amazon-dynamodb filtering aws-glue