如果与 id 不匹配，如何增加循环？

Question

我正在编写一个显示来自 AWS 服务器的图像的代码。但是我在循环代码时遇到了麻烦。

第一次显示效果很好，但不能更进一步（我最多显示 6 张图像）

代码 -

def get_image_urls(user)
        user_identifications = user.user_identifications.where(current_flag: true).order(:id_dl)
        urls = []
        keys = []
        if !user_identifications.empty? && !user_identifications.nil?
            user_identifications.each_with_index do |each_id, index|
                obj = S3_BUCKET.object(each_id.aws_key)
                urls << {each_id.id_dl=> obj.presigned_url(:get)}
                keys << {each_id.id_dl=> each_id.aws_key}
            end
        end
        return urls, keys
    end

如何根据 id 和 user.identifications 值增加循环？

Answer 1

reject所有空值然后迭代users_identifications。 喜欢：

sanitized_identifications = users_identifications.reject(&:blank?)
sanitized_identifications.each_with_index do |identification, _index|
  # Now if you want to skip an iteration based on some condition, try `next`, like:
  # next if some_condition
  # in you case
  obj = S3_BUCKET.object(each_id.aws_key)
  next if obj.blank?
  urls << {each_id.id_dl=> obj.presigned_url(:get)}
  keys << {each_id.id_dl=> each_id.aws_key}
end

更新

# ...
user_identifications.each_with_index do |each_id, index|
  begin
    obj = S3_BUCKET.object(each_id.aws_key)
    urls << {each_id.id_dl=> obj.presigned_url(:get)}
    keys << {each_id.id_dl=> each_id.aws_key}
  rescue => e
    next
  end
end
#...

干杯！