【问题标题】:Django using form input to query data -- should be simple, isn't (for me)Django 使用表单输入来查询数据——应该很简单,不是(对我来说)
【发布时间】:2013-01-04 18:30:54
【问题描述】:

我有一个如下所示的表单:

class AddressSearchForm(forms.Form):
    """
        A form that allows a user to enter an address to be geocoded
    """
    address = forms.CharField()

我没有存储这个值,但是,我正在对地址进行地理编码并检查以确保它有效:

def clean_address(self):
    address = self.cleaned_data["address"]
    return geocode_address(address, True)

地理编码函数如下所示:

def geocode_address(address, return_text = False):
    """ returns GeoDjango Point object for given address
        if return_text is true, it'll return a dictionary: {text, coord}
        otherwise it returns {coord}
    """ 
    g = geocoders.Google()
    try:
        #TODO: not really replace, geocode should use unicode strings
        address = address.encode('ascii', 'replace')            
        text, (lat,lon) = g.geocode(address)
        point = Point(lon,lat)
   except (GQueryError):
       raise forms.ValidationError('Please enter a valid address')
    except (GeocoderResultError, GBadKeyError, GTooManyQueriesError):
    raise forms.ValidationError('There was an error geocoding your address. Please try again')
    except:
        raise forms.ValidationError('An unknown error occured. Please try again')

    if return_text:
         address = {'text':text, 'coord':point}
    else:
        address = {'coord':point}

    return address

我现在需要做的是创建一个视图,该视图将使用地址数据查询模型以过滤结果。我很难弄清楚如何做到这一点。如果可能的话,我想使用 CBV。我可以用FormView来显示表单,用ListView来显示查询结果,但是如何在两者之间传递表单数据呢?

提前致谢。

更新:我知道如何查询我的模型来过滤结果。我只是不知道如何正确组合使用基于表单和基于类的视图,以便我可以访问我的过滤器的cleaned_data。例如:

流程应该是:

1) 在获取时显示表单 2)提交表格并在帖子上验证(地理编码地址) 3) 运行查询并显示结果

address = form.cleaned_data['address']
point = address['coord']
qs = model.objects.filter(point__distance_lte=(point, distance)

【问题讨论】:

    标签: django forms views django-class-based-views


    【解决方案1】:

    好的,这是一个基于 psjinx 方向的通用版本:

    from django.views.generic.base import TemplateResponseMixin, View
    from django.views.generic.edit import FormMixin
    from django.views.generic.list import MultipleObjectMixin
    
    class SearchView(FormMixin, MultipleObjectMixin, TemplateResponseMixin, View):
        """
         A View which takes a queryset and filters it via a validated form submission
        """
        queryset = {{ initial queryset }} # you can use a model here too eg model=foo
        form_class = {{ form }}
    
        def get(self, request, *args, **kwargs):
            form_class = self.get_form_class()
            form = self.get_form(form_class)
            return self.render_to_response(self.get_context_data(form=form))
    
        def post(self, request, *args, **kwargs):
            form_class = self.get_form_class()
            form = self.get_form(form_class)
            if form.is_valid():
                return self.form_valid(form)
            else:
                return self.form_invalid(form)    
    
        def form_valid(self, form):
            queryset = self.get_queryset()
            search_param = form.cleaned_data['{{ form field }}']
            object_list = queryset.filter({{ filter operation }}=search_param)
            context = self.get_context_data(object_list=object_list, form=form, search_param=search_param)
            return self.render_to_response(context) 
    

    【讨论】:

      【解决方案2】:

      这类似于此处提出的问题,或者我会说两个问题的组合。

      1. Django: Search form in Class Based ListView
      2. Search multiple fields of django model without 3rd party app
      3. django simple approach to multi-field search(如果您的模型与本问题中提到的模型相似)

      请查看上述问题及其答案,如果您仍有任何问题,请在评论中回复此答案。


      更新 1

      from django.views.generic.base import TemplateResponseMixin, View
      from django.views.generic.edit import FormMixin
      from django.views.generic.list import MultipleObjectMixin
      
      class SearchView(FormMixin, MultipleObjectMixin, TemplateResponseMixin, View):
          model = SomeModel
          form_class = AddressSearchForm
          template = "search.html"
      
          def get_queryset():
              ## Override it here
              pass
      
          def post():
              ## If your form is invalid then request won't reach here
              ## because FormMixin is in left most position
              ## do something
              ## call self.render_to_response()
      
          def form_valid():
              ## Your form is valid do something
              ## if form is invalid then next method will be called
              pass
      
          def form_invalid(self):
              ## form is not valid
              ## render to some template
      

      有用的链接:

      1. https://github.com/django/django/blob/1.4.3/django/views/generic/base.py
      2. https://github.com/django/django/blob/1.4.3/django/views/generic/edit.py
      3. https://github.com/django/django/blob/1.4.3/django/views/generic/list.py

      相关问题:

      1. Django - Mixing ListView and CreateView

      【讨论】:

      • 它类似于问题 1。但是,该问题的答案是使用硬编码形式的 GET。我想使用带有 POST 的 Form 类,以便我可以在该字段上进行验证。该答案还显示了使用 FBV 的解决方案,但如果可能,我想使用 CBV。我在这里找到了一些关于使用 mixins 执行类似操作的有用信息:docs.djangoproject.com/en/dev/topics/class-based-views/mixins,但没有什么能完全回答我的用例。
      • 请看我更新的答案。我已经为您的视图添加了代码骨架。
      • 谢谢,这真的很有帮助。我会试一试,看看我能不能让它工作。
      • 好的。如果您遇到任何问题,请告诉我。
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