【发布时间】:2020-11-13 12:11:25
【问题描述】:
我的代码用于输入
<input id="imgages" name="imgages" type="file" onchange="uploadFile()" />
我的脚本是:
function _(el) {
return document.getElementById(el);
}
function uploadFile() {
var file = _("imgages").files[0];
var formdata = new FormData();
formdata.append("imgages", file);
var ajax = new XMLHttpRequest();
ajax.upload.addEventListener("progress", progressHandler, false);
ajax.addEventListener("load", completeHandler, false);
ajax.addEventListener("error", errorHandler, false);
ajax.addEventListener("abort", abortHandler, false);
ajax.open("POST", "file_upload_parser.php");
ajax.send(formdata);
}
function progressHandler(event) {
_("loaded_n_total").innerHTML = "Uploaded " + event.loaded + " bytes of " + event.total;
var percent = (event.loaded / event.total) * 100;
_("progressBar").value = Math.round(percent);
_("status").innerHTML = Math.round(percent) + "% uploaded... please wait";
}
function completeHandler(event) {
_("status").innerHTML = event.target.responseText;
_("progressBar").value = 0; //wil clear progress bar after successful upload
}
function errorHandler(event) {
_("status").innerHTML = "Upload Failed";
}
function abortHandler(event) {
_("status").innerHTML = "Upload Aborted";
}
我的问题是我如何才能将这部分转换为使用 laravel 的 url 并在这个 ajax 部分中添加 csrf? 我的意思是我不知道如何在这个脚本中添加 csrf token laravel。
ajax.open("POST", "file_upload_parser.php");
【问题讨论】:
标签: laravel input file-upload progress-bar csrf-token