如何上传 csv 文件并更新 mysql 数据库？ [关闭]

Question

我想使用 csv 文件来更新 mysql scv 表。如何编码？我没有从事这项工作的经验。

<p>please select a scv file to upload</p>
<form action="index.php" method="post">
    <input type="file" name="scv"  />
    <input type="submit" value="submit" />
</form>
<?php 
    mysql_connect('localhost','root','admin');
    mysql_select_db('linjuming');
    // how to upload a scv file and insert or update the "csv" table?

?>

Answer 1

您的上传文件：

<form action="upload_target.php" method="post" enctype="multipart/form-data">
<label for="file">Filename:</label>
<input type="file" name="file" id="file"><br>
<input type="submit" name="submit" value="Submit">
</form>

你的upload_target.php

$ext = pathinfo($_FILES['file']['name'], PATHINFO_EXTENSION);

if ($ext == "csv" && $_FILES["file"]["error"] == 0)
{
    $target = "upload/" . $_FILES["file"]["name"];
    move_uploaded_file($_FILES["file"]["tmp_name"], $target);

    if (($handle = fopen($target, "r")) !== FALSE) 
    {
        while (($data = fgetcsv($handle, 1000, ";")) !== FALSE) 
        {
            print_r($data);
        }

        fclose($handle);
    }
}

非常基本，几乎没有检查/验证。 print_r($data) 包含您现在可以插入数据库的一行 csv。

但是，我建议使用 PDO 或 MySQLi 来完成该任务，因为 PHP 的 mysql 函数将来会被弃用。

Answer 2

这有几个部分：

首先，您的表单必须设置 enctype，如下所示：

<form enctype="multipart/form-data"  action="index.php" method="post">

否则将不接受文件上传。

完成此操作后，您可以使用$_FILES 变量访问该文件。文件上传后，您可以像这样访问它：

if (isset($_FILES["scv"])) {
    $file = $_FILES["scv"];
    $file_name = $file["name"];
    $ext = pathinfo($file_name, PATHINFO_EXTENSION);
    if ($ext!="CSV" && $ext!="TXT") {
        die('The file must be csv or txt format.');
    }
    $saveto_path_and_name = '/path/to/file.csv'; // Where you want to save the file
    move_uploaded_file($file["tmp_name"], $saveto_path_and_name);
}

保存文件后，您可以打开并导入它。这并非易事，但这里有一些入门代码：

// Open the file for reading
$handle = @fopen($saveto_path_and_name, "r") or die(__("Unable to open uploaded file!", "inventory"));
// Grab the first row to do some checks
$row = fgets($inv_file, 4096);
// See if it's comma or tab delimited
if (stripos($inv_row, "\t")) {
    $sep = "\t";
} else {
    $sep = ",";
}

while ( ! feof($handle)) {
    $rowcount = 0;
    // Get the individual fields
    $inv_fields = explode($sep, $inv_row);
    $fields = array();
    // Iterate through the fields to do any sanitization, etc.
    foreach ($inv_fields as $field) {
        // Highly recommended to sanitize the variable $field here....
        $fields[] = $field;
        $rowcount++;
}
    // This is where you would write your query statement to insert the data
    // This is just EXAMPLE code.  Use the DB access of your choice (PDO, MySQLi)
    $sql = vsprintf('INSERT INTO `table` (`column`, `column2`, ...) VALUES (%s, %d, ...)', $fields);
    // Get the next row of data from the file
    $row = fgets($inv_file, 4096);
}