需要将 $_POST['link'] 添加到任何上传的文件名中答案

【问题标题】：Need to add $_POST['link'] to the file name for anything uploaded需要将 $_POST['link'] 添加到任何上传的文件名中
【发布时间】：2020-08-19 01:50:20
【问题描述】：

我很难弄清楚如何将 $_POST['link'] 的值附加到正在上传到我的 upload.php 脚本的文件的前缀中。我已经尝试了很多东西和两个多小时的谷歌搜索。但是，我无法理解需要更改的内容。我已经为这个项目编写脚本十天了，我开始精疲力尽了。您可以提供的任何建议都会真正帮助我，我们将不胜感激。

<?php
$target_dir = "../../uploads/";
$target_file = $target_dir . basename($_FILES["fileToUpload"]["name"]);
$uploadOk = 1;
$imageFileType = strtolower(pathinfo($target_file,PATHINFO_EXTENSION));
// Check if image file is a actual image or fake image
if(isset($_POST["submit"])) {
    $check = getimagesize($_FILES["fileToUpload"]["tmp_name"]);
    if($check !== false) {
        echo "File is a Video- " . $check["mime"] . ".";
        $uploadOk = 1;
    } else {
        $uploadOk = 1;
    }
}
// Check if file already exists
if (file_exists($target_file)) {
    echo "Sorry, file already exists.";
    $uploadOk = 0;
}
// Check file size
if ($_FILES["fileToUpload"]["size"] > 400000000000000000) {
    echo "Sorry, your file is too large.";
    $uploadOk = 0;
}
// Allow certain file formats
if($imageFileType != "webm" && $imageFileType != "mpg" && $imageFileType != "mpeg" && $imageFileType != "mp4" && $imageFileType != "m4p" && $imageFileType != "m4v" && $imageFileType != "avi" && $imageFileType != "wmv" && $imageFileType != "mov" ) {
    echo "Sorry, only WEBM, MPG, MPEG, MP4, M4P, M4V, AVI, WMV, MOV files are allowed.";
    $uploadOk = 0;
}
// Check if $uploadOk is set to 0 by an error
if ($uploadOk == 0) {
    echo "Sorry, your file was not uploaded.";
// if everything is ok, try to upload file
} else {
    if (move_uploaded_file($_FILES["fileToUpload"]["tmp_name"], $target_file)) {
        echo "The file ". basename( $_FILES["fileToUpload"]["name"]). " has been uploaded.";
    } else {
        echo "Sorry, there was an error uploading your file.";
    }
}

echo $_POST['link'];
?>

【问题讨论】：

更改这一行更简单$target_file = $target_dir . $_POST['link'] . basename($_FILES["fileToUpload"]["name"]);

标签： php file-upload upload

【解决方案1】：

错别字，或者用户定义的第一个嵌套if条件错误：else { $uploadOk = 1;}，即使流程不正确也会返回true，先改成else {$uploadOk = 0;}

要为上传文件的值添加前缀，只需这样做

$myprefix = "VID";
$client_filename = $_FILES["uploaded_file"]["name"];
$final_name = $myprefix . $client_filename;
$path = "path/to/folder/" .  $final_name;

然后在上传时，使用新名称：

move_uploaded_file($_FILES["uploaded_file"], $path);

【讨论】：