ASP.NET Razor 文件上传答案

【问题标题】：ASP.NET Razor File UploadASP.NET Razor 文件上传
【发布时间】：2018-01-21 16:59:55
【问题描述】：

我在 MS 网站上关注此示例，以使用 Razor 和 C# 进行文件上传。

如果我有多个文件上传按钮，C# 代码如何知道上传文件来自哪个按钮？根据上传文件的按钮，我会将文件保存到特定文件夹。

https://docs.microsoft.com/en-us/aspnet/web-pages/overview/data/working-with-files

@using Microsoft.Web.Helpers;
    @{
        var fileName = "";
        if (IsPost) {
            var fileSavePath = "";
            var uploadedFile = Request.Files[0];
            fileName = Path.GetFileName(uploadedFile.FileName);
            fileSavePath = Server.MapPath("~/App_Data/UploadedFiles/" +
              fileName);
            uploadedFile.SaveAs(fileSavePath);
        }
    }
    <!DOCTYPE html>
    <html>
        <head>
        <title>FileUpload - Single-File Example</title>
        </head>
        <body>
        <h1>FileUpload - Single-File Example</h1>
        @FileUpload.GetHtml(
            initialNumberOfFiles:1,
            allowMoreFilesToBeAdded:false,
            includeFormTag:true,
            uploadText:"Upload")
        @if (IsPost) {
            <span>File uploaded!</span><br/>
        }
        </body>
    </html>

【问题讨论】：

标签： c# asp.net razor file-upload

【解决方案1】：

这样做的方法是将按钮命名相同，但赋予它们不同的值。然后你可以做一个case语句并根据值来指导逻辑。

剃须刀

@using (Html.BeginForm("Index", "Home", FormMethod.Post, new { enctype = "multipart/form-data" }))
{

    <input type="file" name="FirstUpload" />
    <input type="submit" name="submitID" id="submitID" value="Upload1" />

    <input type="file" name="SecondUpload" />
    <input type="submit" name="submitID" id="submitID" value="Upload2" />

}

控制器

public ActionResult Index()
        {
            return View();
        }

        [HttpPost]
        public ActionResult Index(FormCollection collection)
        {
            string btn = Request.Params["submitID"];

            switch (btn)
            {
                case "Upload1":

                    for (int i = 0; i < Request.Files.Count; i++)
                    {
                        var file = Request.Files[i];
                    }                      
                    break;

                case "Upload2":

                    for (int i = 0; i < Request.Files.Count; i++)
                    {
                        var file = Request.Files[i];
                    }
                    break;
            }

            return View();
        }

【讨论】：

【解决方案2】：

我遇到了类似的问题，最后得到了以下代码：
Razor

//BeginForm and other staff
@foreach (var d in Model.Types)
{
    <input type="file" name="doc:@d.Id:upload" />//@d.Id is the key point
    <button formenctype="multipart/form-data"
      type="submit" formaction="/MyController/uploaddoc" 
      name="typeid" formmethod="post" value="@d.Id">//this way I send Id to controller
       Upload
    </button>
}

我的控制器

[HttpPost]
[ValidateAntiForgeryToken]
[Route("mycontroller/uploaddoc")]//same as formaction
public async Task<ActionResult> UploadDoc(FormCollection data, int typeid)
{
    //restore inpput name
    var fl = Request.Files["doc:" + typeid.ToString() + ":upload"];
    if (fl != null && fl.ContentLength > 0)
    {
        var path = Server.MapPath("~/app_data/docs");
        var fn = Guid.NewGuid().ToString();//random name
        using (FileStream fs = System.IO.File.Create(Path.Combine(path, fn)))
        {
            await fl.InputStream.CopyToAsync(fs);
        }
    }

}

【讨论】：