无法在jsp中下载.xlsx文件答案

【问题标题】：No able to download .xlsx file in jsp无法在jsp中下载.xlsx文件
【发布时间】：2020-03-21 20:48:58
【问题描述】：

我为下载文件编写了如下代码：

String filename = request.getParameter("file").toString();   
String filepath = request.getParameter("path").toString(); ;  
response.setContentType("APPLICATION/OCTET-STREAM");   
response.setHeader("Content-Disposition","attachment; filename=\"" + filename + "\"");   
FileInputStream fileInputStream=new FileInputStream(filepath + filename);         
int i;   

while ((i = fileInputStream.read()) != -1) {  
    out.write(i);
}   

fileInputStream.close();

【问题讨论】：

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标签： java file jsp file-upload

【解决方案1】：

我在带有 scriplet 标签的 jsp 页面中使用此代码，即

现在我在 servlet 中尝试过，现在可以打开 .xlsx 文件。工作代码如下：

 protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
        // TODO Auto-generated method stub



          String filename = request.getParameter("file").toString();   
          String filepath = request.getParameter("path").toString();  

         File f = new File (filepath + filename);
         //set the content type(can be excel/word/powerpoint etc..)

         String type = request.getParameter("type");
         response.setContentType (type);

         //set the header and also the Name by which user will be prompted to save
         response.setHeader ("Content-Disposition", "attachment; filename=\""+filename+"\"");

         //get the file name
         String name = f.getName().substring(f.getName().lastIndexOf("/") + 1, f.getName().length());

         //OPen an input stream to the file and post the file contents thru the 
         //servlet output stream to the client m/c
          InputStream in = new FileInputStream(f);

        try{
              ServletOutputStream outs = response.getOutputStream();

              int bytesRead;
              byte[] buf = new byte[4 * 1024]; // 4K buffer

              try {
                   while ((bytesRead = in.read(buf)) != -1){ 
                       outs.write(buf, 0, bytesRead);
                   }

              } catch (IOException ioe) {
                  ioe.printStackTrace(System.out);
              }


              outs.flush();
              outs.close();
              in.close(); 
        }catch(Exception e){
            e.printStackTrace();
        }
    }

【讨论】：