将 Led 重置为 LOW 从 Visual Studio 到 arduino

Question

我希望能够使用 arduino 中的按钮打开红色 LED，并能够使用 Visual Studio 中的重置按钮将其重置。问题是它要么继续并且无法从重置按钮打开，要么它关闭并且如果程序没有重新启动则无法再次打开。我会感谢所有帮助。

LED 的 arduino 代码。

    void setup() {
      Serial.begin(9600);
      pinMode(BUTTON_SWITCH, INPUT_PULLUP);
      pinMode(BUTTON_ALARM, INPUT_PULLUP);
      pinMode(RED_LED, OUTPUT);

    }

if (digitalRead(BUTTON_ALARM) == LOW) {
    displayAlarm();
  }

   void displayAlarm() {
  digitalWrite(RED_LED, HIGH);
  tone(BUZZER, 1500, 700);
    if (Serial.available()) {
        // Read entire buffer up to newline character
        // Since on the C# side, serialPort1.WriteLine appends a newline character
        String respond = Serial.readStringUntil('\n');
        if (respond == "RESET") {
            digitalWrite(RED_LED, LOW);
            digitalWrite(BUZZER, LOW);
        }
    }

重置按钮中的 Visual Studio 代码。

 private void Button1_Click(object sender, EventArgs e)
    {

            serialPort1.WriteLine("RESET");


    }

Answer 1

您已经创建了一个float 变量respond。这是一个数值而不是字符串，但“RESET”是一个字符串，您无法真正将数字与字符串进行比较。您需要将respond 设为String 并使用readStringUntil() 阅读整行：

void setup()
{
    Serial.begin(9600);
    pinMode(BUTTON_SWITCH, INPUT_PULLUP);
    pinMode(BUTTON_ALARM, INPUT_PULLUP);
    pinMode(RED_LED, OUTPUT);
}

void loop()
{
    // If BUTTON_ALARM pressed, enable alarm
    if (digitalRead(BUTTON_ALARM) == LOW) {
        displayAlarm();
    }

    // Check if there is data in the serial port input buffer
    // If there is and it is "RESET", disable the alarm
    if (Serial.available()) {
        // Read entire buffer up to newline character
        // Since on the C# side, serialPort1.WriteLine appends a newline character
        String respond =Serial.readStringUntil('\n');
        if (respond == "RESET") {
            digitalWrite(RED_LED, LOW);
            digitalWrite(BUZZER, LOW);
        }
    }
}

void displayAlarm()
{
    digitalWrite(RED_LED, HIGH);
    tone(BUZZER, 1500, 700);
}

默认情况下，WriteLine 附加一个换行符。确保你没有修改它。见：SerialPort.NewLine Property