include() 得到了一个意外的关键字参数“app_name”答案

【问题标题】：include() got an unexpected keyword argument 'app_name'include() 得到了一个意外的关键字参数“app_name”
【发布时间】：2018-06-19 01:53:27
【问题描述】：

我正在使用 django-2.0 为我的网站制作博客应用程序当我运行服务器时，我看到以下错误

File "C:\Users\User\Desktop\djite\djite\djite\urls.py", line 7, in <module>
url(r'^blog/', include('blog.urls', namespace='blog', app_name='blog')),
TypeError: include() got an unexpected keyword argument 'app_name'

这是我的主要 urls.py

from django.contrib import admin
from django.conf.urls import url,include

urlpatterns = [
    url(r'^admin/', admin.site.urls),

    url(r'^blog/', include('blog.urls', namespace='blog', app_name='blog')),
]

这是我的博客/urls.py

from django.conf.urls import url
from . import views
urlpatterns = [
    url(r'^$', views.post_list, name='post_list'),
    url(r'^(?P<year>\d{4})/(?P<month>\d{2})/(?P<day>d{2})/(?P<post>
    [-/w]+)/$', views.post_detail, name='post_detail'),
    ]

我的意见.py：

from django.shortcuts import render, HttpResponse, get_object_or_404
from blog.models import Post
def post_list(request): #list
posts=Post.published.all()
return render(request, 'blog/post/list.html', {'posts': posts})

def post_detail(request, year, month, day, post):
    post =get_object_or_404(post, slog=post,
                              status='published',
                              publush__year=year,
                              publish__month=month,
                              publish__day=day)
    return render (request, 'blog/post/detail.html', {'post':post})

models.py：

# -*- coding:utf-8 -*-
from django.db import models
from django.conf import settings
from django.utils import timezone
from django.contrib.auth.models import User
from django.utils.translation import ugettext_lazy as _
from django.urls import reverse
class PublishedManager(models.Manager):
    def get_queryset(self):
        return super(PublishedManager, 
        self).get_queryset().filter(status='published')

class Post(models.Model):
    STATUS_CHOICES = (
        ('draft', 'Draft'),
        ('published', 'Published'),
    )
    title = 
    models.CharField(max_length=255,verbose_name=_('title'),help_text=_('add 
    title'))
    content = models.TextField(verbose_name=_('content'),help_text=_('write 
    here'))
    publish = models.DateTimeField(default=timezone.now)
    createtime = models.DateTimeField(_('create time'),auto_now_add=True, 
    auto_now=False,help_text=_('create time'))
    updatetime = models.DateTimeField(_('update time'),auto_now_add=False, 
    auto_now=True,help_text=_('update time'))
    author = models.ForeignKey(settings.AUTH_USER_MODEL, 
    verbose_name=_('author'), 
    on_delete=models.DO_NOTHING,help_text=_('choose author'))
    slug = models.SlugField(unique=True, max_length=255,help_text=_('add 
    slug'))
    status = models.CharField(max_length=10, choices=STATUS_CHOICES, 
    default='draft')


    def __unicode__(self):
        return self.title

    def __str__(self):
        return self.title

    class Meta:
        ordering = ('-publish',)
        verbose_name = _('Post')
        verbose_name_plural = _('Posts')


    def get_absolute_url(self):
        return reverse('blog:post_detail', args=[self.publish.year,
                                         self.publish.strftime('%m'),
                                         self.publish.strftime('%d'),
                                         self.slug])

当我删除时，我的 views.py 也有一个问题，我认为这与我当前的错误无关

namespace='blog', app_name='blog'

从主 urls.py 中的这一行

url(r'^blog/', include('blog.urls', namespace='blog', app_name='blog')),

服务器运行但是当我进入这个目录时：

http://localhost:8000/blog/

我看到了这个错误

AttributeError at /blog/
type object 'Post' has no attribute 'published'

说这行代码在views.py中有问题

 posts=Post.published.all()

【问题讨论】：

标签： django django-models django-views django-urls django-2.0

【解决方案1】：

在 Django 1.9 中不推荐使用 app_name 和 include，并且在 Django 2.0 中不起作用。在blog/urls.py 中设置app_name。

app_name = 'blog'
urlpatterns = [
    url(r'^$', views.post_list, name='post_list'),
    ...
]

然后将包含更改为：

url(r'^blog/', include('blog.urls')),

您不需要namespace='blog'，因为无论如何它都会默认为应用程序命名空间。

第二个错误无关。您忘记在模型上实例化您的自定义管理器。

class Post(models.Model):
    ...
    published = PublishedManager()

【讨论】：

【解决方案2】：

在 Django 2.0 app_name 中，将不支持：

项目网址的使用：

from django.contrib import admin
from django.urls import include, path

urlpatterns = [
    path('admin/', admin.site.urls),
    path(r'blog/', include('blog.urls')),//use this 
]

【讨论】：