Django：如何显示内联表单集中每个模型对象的表单错误

Question

我有一个作者模型和一个书籍模型。用户可以修改给定作者的所有书籍的属性。我希望能够显示每本书的错误，而不是将所有错误都列在顶部，我该怎么做？

模型

from django.db import models
from django.forms import ModelForm, Textarea
from django import forms

class Author(models.Model):
    fname = models.CharField(max_length=100)
    lname = models.CharField(max_length=100)
    def fullname(self):
        return '%s %s' % (self.fname, self.lname)
    fullname = property(fullname)
    def __unicode__(self):
        return self.fullname

class Books(models.Model):
    author = models.ForeignKey(Author)
    title = models.CharField(max_length=50)
    publisher = models.CharField(max_length=50)
    edition = models.CharField(max_length=50)
    comment = models.TextField()
    def __unicode__(self):
         return self.title

查看

def author_books_edit(request, author_id):
    a = get_object_or_404(Author, pk=author_id)
    authorsbooks = a.books_set.all()
    bookformset = inlineformset_factory(Author, Books, can_delete=True, can_order=True, exclude=('company',), extra=1)
    formset = bookformset(instance=a)
    if request.method == "POST":
        formset = bookformset(request.POST, request.FILES, instance=a)
        if formset.is_valid():
            formset.save()
        else:
            form_errors = formset.errors
            return render_to_response('test/authors_books_edits.html', {'author': a, 'authorsbooks': authorsbooks, 'formset': formset, 'form_errors': form_errors}, context_instance=RequestContext(request))
    return render_to_response('test/authors_books_edits.html', {'author': a, 'authorsbooks': authorsbooks, 'formset': formset,}, context_instance=RequestContext(request))

模板

#all errors are here
{% for dict in form_errors %}
    {{ dict }}
{% endfor %}

#all forms are here, i want to pair the errors for each form
<form method="post" action="/test/{{ author.id }}/books/">
    {% csrf_token %}
        <table>
        {{ formset }}
        </table>
    <input type="submit" value="Submit"/>
    </form>

更新的模板：不显示错误

<form method="post" action="/test/{{ author.id }}/books/">
    {% formset.management_form %}
    {% csrf_token %}
    <table>
        {% for x in formset %}
        {{x.errors }}
        {{ x }}
        {% endfor %}
    </table>
<input type="submit" value="Submit"/>

Answer 1

编辑

authors_books_edits.html

<form method="post" action="/test/{{ author.id }}/books/">
    {% csrf_token %}
    {{ formset.management_form }}
    {% for form in formset.forms %}
        {{ form.non_field_errors }}
        {{ form.errors }}
        <table>
            {{ form.as_table }}
        </table>
    {% endfor %}
    <input type="submit" value="Submit"/>
</form>

views.py

from django.shortcuts import *
from django.forms.models import inlineformset_factory

from .models import *

def author_books_edit(request, author_id):
    a = get_object_or_404(Author, pk=author_id)
    authorsbooks = a.books_set.all()
    bookformset = inlineformset_factory(Author, Books, can_delete=True, can_order=True, exclude=('company',), extra=1)
    formset = bookformset(instance=a)
    if request.method == "POST":
        formset = bookformset(request.POST, request.FILES, instance=a)
        if formset.is_valid():
            formset.save()
        else:
            form_errors = formset.errors
            return render_to_response('authors_books_edits.html', {'author': a, 'authorsbooks': authorsbooks, 'formset': formset, 'form_errors': form_errors}, context_instance=RequestContext(request))
    return render_to_response('authors_books_edits.html', {'author': a, 'authorsbooks': authorsbooks, 'formset': formset,}, context_instance=RequestContext(request))

models.py

from django.db import models

class Author(models.Model):
    fname = models.CharField(max_length=100)
    lname = models.CharField(max_length=100)
    def fullname(self):
        return '%s %s' % (self.fname, self.lname)
    fullname = property(fullname)
    def __unicode__(self):
        return self.fullname

class Books(models.Model):
    author = models.ForeignKey(Author)
    title = models.CharField(max_length=50)
    publisher = models.CharField(max_length=50)
    edition = models.CharField(max_length=50)
    comment = models.TextField()
    def __unicode__(self):
         return self.title

urls.py

from django.conf.urls.defaults import patterns, include, url

urlpatterns = patterns('testapp.views',
    url(r'test/(?P<author_id>\d+)/books/$', 'author_books_edit'),
)

您可以制作另一个临时应用来测试它。

看起来像这样：http://imageshack.us/photo/my-images/824/screenshotat20120227190.png/

== 结束编辑

您可以像这样迭代表单：

{% for form in formset.forms %}
   {{ form }}
{% endfor %}

在这种情况下，请参阅 Django 使用模板文档显示表单：https://docs.djangoproject.com/en/dev/topics/forms/#displaying-a-form-using-a-template

然后，更有趣的是，自定义表单模板（请参阅 form.non_field_errors）： https://docs.djangoproject.com/en/dev/topics/forms/#customizing-the-form-template

Answer 2

假设这本书是一种你可以做到的形式：

{% for b in authorsbooks %}
    {{b.errors}}
{% endfor %}