如何在 Django 中按类别筛选产品？

Question

我正在尝试根据类别进行过滤，但它在每个类别页面上显示所有产品，但我想根据类别页面进行过滤，请检查我的代码并告诉我该怎么做。

这是我的models.py 文件...

 class SubCategory(models.Model):
        subcat_name=models.CharField(max_length=225)
        subcat_slug=models.SlugField(max_length=225, unique=True)
        category = models.ForeignKey('Category', related_name='subcategoryies', on_delete=models.CASCADE, blank=True, null=True)

and here is my product models.py file...

    class Product(models.Model):
        name=models.CharField(max_length=225)
        slug=models.SlugField(max_length=225, unique=True)
        subcategory=models.ForeignKey('SubCategory', related_name='prosubcat', on_delete=models.CASCADE, blank=True, null=True)

        def __str__(self):
            return self.name


class ProductFilter(django_filters.FilterSet):
    name = django_filters.CharFilter(lookup_expr='icontains')
    class Meta:
        model = Product
        fields = ['saleprice', 'title','veg_non','brand','supplement']

def SubCategorySlugListAPIView(request, subcat_slug):
    category = Category.objects.all()
    subcategories = SubCategory.objects.all()
    product = Product.objects.all()
    brands=Brand.objects.all()
    f = ProductFilter(request.GET, queryset=Product.objects.all())
    supplement=Supplement.objects.all()
    featured=Product.objects.filter(featured=True).order_by('-created_at')[0:6]
    high = Product.objects.all().order_by('-saleprice')
    if subcat_slug:
        subcategory = get_object_or_404(SubCategory, subcat_slug=subcat_slug)
        productlist = product.filter(subcategory=subcategory)
        paginator = Paginator(productlist, 12)
        page_number = request.GET.get('page')
        product = paginator.get_page(page_number)
    template_name = 'mainpage/cat-products.html'
    context = {'product': product,
           'subcategories': subcategories, 'subcategory': subcategory, 'category': category, 'featured':featured, 'high':high, 'brands':brands, 'supplement':supplement, 'filter':f}
    return render(request, template_name, context)

我知道需要合并这些代码 f = ProductFilter(request.GET, queryset=Product.objects.all()) 和这个productlist = product.filter(subcategory=subcategory)，使用productlist 我根据类别获取产品但是当我使用filter 进行过滤时，所有产品都会显示在每个类别页面上.请合并这两个代码并给我一个正确的解决方案。

Answer 1

例如：

在models.py

from django.db import models

class Category(model.Model):
    slug = models.SlugField(unique=True, max_length=50)

class Item(model.Model):
    category = models.ManyToManyField(Category,related_name='ITEM')

在views.py

from django.shortcuts import render, get_object_or_404
from .models import Category

def category_filter(request, slug):
    category = get_object_or_404(Category, slug=slug)
    data = category.ITEM.all()
    render(request, TEMPLATE_NAME, context={'data':data})

在 urls.py 中

from django.urls import path
from .views import category_filter

urlpatterns = [
    path('category/<slug:slug>/', category_filter, name='Category'),
]

现在如果 url 类似于

本地主机/类别/froots/

将显示所有具有 froot 类别的项目。

Answer 2

你可以试试这个。

def SubCategorySlugListAPIView(request, subcat_slug):
    
    # First get the category object.
    subcategory = get_object_or_404(SubCategory, subcat_slug=subcat_slug)
    
    # then filter the products on this category

    productlist =Product.objects.filter(subcategory=subcategory)

编辑：这里没有必要编写额外的filter 方法。 您需要的基本内容是您需要首先获取单个类别对象并从产品模型中过滤该类别的产品。

def SubCategorySlugListAPIView(request, subcat_slug):
    subcategory = get_object_or_404(SubCategory, subcat_slug=subcat_slug)
    productlist = Product.objects.filter(subcategory=subcategory)
    paginator = Paginator(productlist, 12)
    page_number = request.GET.get('page')
    product = paginator.get_page(page_number)

    brands=Brand.objects.all()
    supplement=Supplement.objects.all()
    featured=Product.objects.filter(featured=True).order_by('-created_at')[0:6]
    high = Product.objects.all().order_by('-saleprice')            
       
    template_name = 'mainpage/cat-products.html'
    context = {'product': product,
           'subcategories': subcategories, 'subcategory': subcategory, 'category': category, 'featured':featured, 'high':high, 'brands':brands, 'supplement':supplement}
    return render(request, template_name, context)

您也可以像这样过滤相关产品（其他方式）

subcategory = get_object_or_404(SubCategory, subcat_slug=subcat_slug)
productlist = subcategory.prosubcat.all()