【发布时间】:2021-08-01 05:20:31
【问题描述】:
我们如何查询和选择通知的特定 id..?
现在我正面临以下问题...您可以在其他部分看到我正在发送通知,说明有人关注了其他人。现在在如果一个人取消关注他关注的人时选择。应该删除该通知,以便当他再次关注时,先前的通知会被删除并生成新的通知。我期待你们的善意和帮助。谢谢!:)
if follower:
profile_.follower.remove(follower.id)
actor = User.objects.get(pk=user_id)
user = User.objects.get(username=username_to_toggle)
query = Notification.objects.filter(id__in=notificacion_ids).update(deleted=True) #notificacion_ids(I don't understand how to get that.)
print(query,"hey heyh eh")
# json_follower = some_view(user)
else:
new_follower = User.objects.get(username__iexact=username_to_toggle)
profile_.follower.add(new_follower.id)
actor = User.objects.get(pk=user_id)
user = User.objects.get(username=username_to_toggle)
notify.send(actor, recipient=user, verb='follow you')
# json_follower = some_view(username_to_toggle)
is_following = True
【问题讨论】:
标签: django api django-models django-views notifications