如何在 iOS 中将从 sqlite 获取的数据显示到 tableview 上

Question

我有一个 json 数据保存在我的 sqlite 数据库中。我从数据库中获取了一个数组（moodsDataArray）中的数据，看起来像这样-

{     

data = "(\n       
{\n        c1 = 8847FF;\n        c2 =    EA8CFF;\n        c3 = D1FFB0;\n        c4 = FF63FC;\n        c5 = 6B6B6B;\n        description = mood;\n        \"font_color\" = 000000;\n        \"font_name\" = Default;\n        \"font_size\" = 3;\n        \"moods_name\" = mood1;\n    },\n        
{\n        c1 = D4FF38;\n        c2 = FFA83D;\n        c3 = FFFA9E;\n        c4 = 66FFBA;\n        c5 = 63FFE8;\n        description = \"this is mood 2\";\n        \"font_color\" = 363636;\n        \"font_name\" = Default;\n        \"font_size\" = 10;\n        \"moods_name\" = mood2;\n    },\n      
{\n        c1 = 52FFA5;\n        c2 = B8F2FF;\n        c3 = FF6EA5;\n        c4 = DFC4FF;\n        c5 = 61FFED;\n        description = \"it is mood 3\";\n        \"font_color\" = 595959;\n        \"font_name\" = Default;\n        \"font_size\" = 4;\n        \"moods_name\" = mood3;\n    },\n       
{\n        c1 = 8791FF;\n        c2 = D8FF63;\n        c3 = 3DFFDB;\n        c4 = C0FF5C;\n        c5 = FF9EE7;\n        description = \"this is mood 4\";\n        \"font_color\" = 242424;\n        \"font_name\" = Serif;\n        \"font_size\" = 4;\n        \"moods_name\" = mood4;\n    },\n    
{\n        c1 = 8AFFFD;\n        c2 = B3FFC3;\n        c3 = DB70FF;\n        c4 = AEFF9C;\n        c5 = 70FDFF;\n        description = \"this is mood 5\";\n        \"font_color\" = 2134FF;\n        \"font_name\" = Monospace;\n        \"font_size\" = 4;\n        \"moods_name\" = mood5;\n    },\n        
{\n        c1 = 6BFF69;\n        c2 = FF575F;\n        c3 = 78FDFF;\n        c4 = 61FF36;\n        c5 = 6D1FFF;\n        description = \"6th mood\";\n        \"font_color\" = 212121;\n        \"font_name\" = Serif;\n        \"font_size\" = 11;\n        \"moods_name\" = mood6;\n    },\n    
{\n        c1 = FFA72B;\n        c2 = FFD8A1;\n        c3 = FFE38F;\n        c4 = FAFFC7;\n        c5 = FFFBC9;\n        description = \"it is mood 9\";\n        \"font_color\" = C66BFF;\n        \"font_name\" = Sans;\n        \"font_size\" = 11;\n        \"moods_name\" = mood9;\n    }\n)";
    message = "moods Details!";
    status = 1;
}

现在我创建了一个表格视图，我必须在其中将标题名称设置为“moods_name”，这是上述数组中的一个键。我在 cellForRowAtIndexPath 中尝试了以下方法，但它对我不起作用。

cell.lblmoodstitle.text=[[_moodsDataArray objectAtIndex:indexPath.row]valueForKey:@"moods_name"];

请帮助我在这里做错了什么？

Answer 1

以上发布的结果为字典格式。有 3 个键：数据、消息和状态。并且这些键中的每一个的值都以字符串形式返回。因此您不能将其作为数组访问。

更新： 对于每个数组元素，您需要包含来自"{" to "}" 的子字符串的字典。所以首先替换所有"\n" by ""(empty space)". 之后replace "\" with ""。现在由于"{" to "}" 中的每个字符串内容都由"," (comma) 分隔，因此使用分隔符","(comma) 拆分字符串。现在您将获得包含来自"{" to "}" including both "{" and "}" 的内容的字符串数组。现在你可以用分隔符" " (single space) 拆分它，这样你就可以得到包含从"c1 = 8847FF" 到"moods_nam" = mood1 的每个元素的数组

但是说真的，将来使用这种方法会变得很乏味。考虑使用其他存储选项，例如 Core Data 或将其以更易于管理的格式存储在 sqlite 中。