【问题标题】:WHY am I getting this NameError : name 'url_for' is not defined? [closed]为什么我得到这个 NameError : name 'url_for' is not defined? [关闭]
【发布时间】:2017-04-13 22:57:51
【问题描述】:

我正在尝试按照烧瓶教程的说明构建一个 URL

http://flask.pocoo.org/docs/0.11/quickstart/

但是我不断收到这个 NameError

名称“url_for”未定义

这是代码:

from flask import Flask

app = Flask(__name__)

@app.route('/')
def Index() : pass

@app.route ('/ login')
def loGin() : pass

@app.route('/user/<username>')
def profile( username) : pass


with app.test_request_context() :
    print url_for('Index')
    print url_for('loGin')
    print url_for('loGin', next='/')
    print url_for('profile', username = 'Jon DD')

这是总的错误信息:

eloiim:minimalapp iivri.andre$ export FLASK_APP=Greet.py
eloiim:minimalapp iivri.andre$ flask run 
Traceback (most recent call last):
  File "/usr/local/bin/flask", line 11, in <module>
    sys.exit(main())
  File "/usr/local/lib/python2.7/site-packages/flask/cli.py", line 478, in main
    cli.main(args=args, prog_name=name)
  File "/usr/local/lib/python2.7/site-packages/flask/cli.py", line 345, in main
    return AppGroup.main(self, *args, **kwargs)
  File "/usr/local/lib/python2.7/site-packages/click/core.py", line 696, in main
    rv = self.invoke(ctx)
  File "/usr/local/lib/python2.7/site-packages/click/core.py", line 1060, in invoke
    return _process_result(sub_ctx.command.invoke(sub_ctx))
  File "/usr/local/lib/python2.7/site-packages/click/core.py", line 889, in invoke
    return ctx.invoke(self.callback, **ctx.params)
  File "/usr/local/lib/python2.7/site-packages/click/core.py", line 534, in invoke
    return callback(*args, **kwargs)
  File "/usr/local/lib/python2.7/site-packages/click/decorators.py", line 64, in new_func
    return ctx.invoke(f, obj, *args[1:], **kwargs)
  File "/usr/local/lib/python2.7/site-packages/click/core.py", line 534, in invoke
    return callback(*args, **kwargs)
  File "/usr/local/lib/python2.7/site-packages/flask/cli.py", line 388, in run_command
    app = DispatchingApp(info.load_app, use_eager_loading=eager_loading)
  File "/usr/local/lib/python2.7/site-packages/flask/cli.py", line 124, in __init__
    self._load_unlocked()
  File "/usr/local/lib/python2.7/site-packages/flask/cli.py", line 148, in _load_unlocked
    self._app = rv = self.loader()
  File "/usr/local/lib/python2.7/site-packages/flask/cli.py", line 209, in load_app
    rv = locate_app(self.app_import_path)
  File "/usr/local/lib/python2.7/site-packages/flask/cli.py", line 89, in locate_app
    __import__(module)
  File "/Users/iivri.andre/Documents/minimalapp/Greet.py", line 16, in <module>
    print url_for('Index')
NameError: name 'url_for' is not defined

我不确定是什么问题。

【问题讨论】:

  • 正如错误所说,因为 url_for 未定义。你需要导入它。 from Flask import url_for
  • 当 Python 说某些东西没有定义,而你认为​​它是,找出它是在哪里定义的。你会发现不是。

标签: python flask web


【解决方案1】:

将其添加到您的导入行:

from flask import Flask, url_for

【讨论】:

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