【发布时间】:2015-01-17 11:26:49
【问题描述】:
我的报告视图中有一个选择菜单,应该允许用户选择多个“状态”,然后在我的控制器中,查询结果应该是所有选定的“状态”。但是我不确定如何格式化 ->whereIn 以包含这些状态。关于我需要做什么的任何想法,我才刚刚开始使用 Laravel。
这是我尝试使用数组的查询部分。也是控制器
public function reportFailedPayments(){
$paymentstatus = Input::get('PaymentStatus');
$startdate = Input::get('startdate');
$enddate = Input::get('enddate');
$status = Input::get('status');
$data = DB::table('Payments')
->join('Customer_Purchases', 'Payments.Purchase_ID','=','Customer_Purchases.Purchase_ID')
->leftJoin(
DB::raw('(Select Payment_ID, max(Process_Hist_ID) AS Process_Hist_ID FROM Payment_Process_History GROUP BY Payment_ID) PHID'), function($join){
$join->on('PHID.Payment_ID', '=', 'Payments.Payment_ID');
})
->leftJoin('Payment_Process_History', 'Payment_Process_History.Process_Hist_ID', '=', 'PHID.Process_Hist_ID')
->leftJoin('Billing_Information', 'Payment_Process_History.Billing_Info_ID', '=', 'Billing_Information.Billing_Info_ID')
->join('Users', 'Users.User_ID', '=', 'Customer_Purchases.User_ID')
->join('Product_Instances', 'Product_Instances.Instance_ID', '=', 'Customer_Purchases.Instance_ID')
->join('Products', 'Products.Product_ID', '=', 'Product_Instances.Product_ID')
->select('Users.First_Name AS First_Name', 'Users.Last_Name AS Last_Name', 'Users.Email AS Email',
'Payments.Payment_Date AS Scheduled_Payment_Date', 'Payments.Pay_Amount As Pay_Amount',
'Products.Name AS Product_Name',
'Customer_Purchases.Purchase_Date As Purchase_Date', 'Payment_Process_History.Process_Time AS Last_Processed',
'Payment_Process_History.Transaction_ID AS Transaction_ID', 'Payment_Process_History.Trans_Response_Code AS Transaction_Code',
'Payment_Process_History.Trans_Response_Text as Transaction_Message', 'Billing_Information.Payment_Type AS Payment_Type', 'Billing_Information.CCType AS CCType', 'Billing_Information.CCLast4 AS CCLast4')
->whereIn('Payments.Status',array($paymentstatus))
->whereBetween('Payments.Payment_Date', array($startdate, $enddate))->get();
return View::make('admin.reports.failedPayments.report')->with(array('payments'=>$data));
在我的视图中选择菜单。
<label for="startdate">Start Date</label><input type="date" id="startdate" value="{{ date('Y-m-d', strtotime("-1 days")) }}" />
<label for="enddate">End Date</label><input type="date" id="enddate" value="{{ date('Y-m- d') }}" />
<label for="status">Status</label><br>
<select multiple="multiple" id="status" name='PaymentStatus'status="Status" size="1">
<option value='ALL'>-- ALL --</option>
<option value='{{ PaymentStatus::Pending}}'>{{ PaymentStatus::toString(PaymentStatus::Pending) }}</option>
<option value='{{ PaymentStatus::Charged}}'>{{ PaymentStatus::toString(PaymentStatus::Charged) }}</option>
<option value='{{ PaymentStatus::Denied}}'>{{ PaymentStatus::toString(PaymentStatus::Denied) }}</option>
<option value='{{ PaymentStatus::Refunded}}'>{{ PaymentStatus::toString(PaymentStatus::Refunded) }}</option>
<option value='{{ PaymentStatus::PendingReview}}'>{{ PaymentStatus::toString(PaymentStatus::PendingReview) }}</option>
<option value='{{ PaymentStatus::Cancelled}}'>{{ PaymentStatus::toString(PaymentStatus::Cancelled) }}</option>
【问题讨论】:
-
$paymentstatus不应该已经是一个数组了吗?所以你可以做whereIn('Payment.Status', $paymentstatus)。如果没有,请告诉我们您是如何获取变量的以及其中的内容 (var_dump) -
我已经尝试过了,并得到“必须是数组类型”错误。我只是想让它按我选择的 Payments.Status 对列表进行排序。在查询上方的控制器中,我正在使用 '$paymentstatus = Input::get('PaymentStatus');
-
select上是否有name属性?因为我在您发布的代码中找不到它 -
我没有,只是 id='status'
-
好吧,如果你不使用一些javascript来提交你的表单,你肯定需要一个
name属性。这是用于将数据发送到服务器的标识符(并通过Input::get()访问它)
标签: laravel laravel-4 eloquent