大括号和main方法中的返回值[重复]

Question

我读到了这个code（作者 Bjarne Stroustrup）。我很困惑...main 函数体不在{} 中，并且函数不返回值（如int）。而且它有效...为什么？

#include "std_lib_facilities.h" 

int main()
try
{
    cout<< "please enter two floating-point values separated by an operator\n The operator can be + - * or / : ";
    double val1 = 0;
    double val2 = 0;
    char op = 0;
    while (cin>>val1>>op>>val2) {   // read number operation number
        string oper;
        double result;
        switch (op) {
        case '+':
            oper = "sum of ";
            result = val1+val2; 
            break;
        case '-':
            oper = "difference between ";
            result = val1-val2; 
            break;
        case '*':
            oper = "product of ";
            result = val1*val2; 
            break;
        case '/':
            oper = "ratio of";
            if (val2==0) error("trying to divide by zero");
            result = val1/val2; 
            break;
        //case '%':
        //  oper = "remainder of ";
        //  result = val1%val2; 
        //  break;
        default:
                error("bad operator");
        }
        cout << oper << val1 << " and " << val2 << " is " << result << '\n';
        cout << "Try again: ";
    }
}
catch (runtime_error e) {   // this code is to produce error messages; it will be described in Chapter 5
    cout << e.what() << '\n';
    keep_window_open("~");  // For some Windows(tm) setups
}
catch (...) {   // this code is to produce error messages; it will be described in Chapter 5
    cout << "exiting\n";
    keep_window_open("~");  // For some Windows(tm) setups
}

Answer 1

该代码使用Function Try Block，这是一种特殊语法，允许将函数的整个主体嵌入到 try/catch 块中（主要用于类构造函数，以便捕获基类构造函数抛出的异常或成员子对象）。

此外，main() 是唯一一个不需要显式返回值的值返回函数。未指定返回值时，假定为0。

根据 C++11 标准的第 3.6.1/5 段：

main 中的 return 语句具有离开 main 函数的效果（使用自动 存储持续时间）并以返回值作为参数调用std::exit。如果控制到达终点 main的没有遇到return语句，效果就是执行

return 0;