【发布时间】：2011-07-31 03:28:08
【问题描述】：
我正在尝试在服务器上上传图像，下面是我在 Internet 上找到并在本地工作的脚本，当我部署代码和数据库时出现“无法打开流：权限被拒绝”错误。
<?php
//define a maxim size for the uploaded images in Kb
define ("MAX_SIZE","5000");
//This function reads the extension of the file. It is used to determine if the file is an image by checking the extension.
function getExtension($str) {
$i = strrpos($str,".");
if (!$i) { return ""; }
$l = strlen($str) - $i;
$ext = substr($str,$i+1,$l);
return $ext;
}
//This variable is used as a flag. The value is initialized with 0 (meaning no error found)
//and it will be changed to 1 if an errro occures.
//If the error occures the file will not be uploaded.
$errors=0;
//reads the name of the file the user submitted for uploading
$image=$_FILES['image']['name'];
//if it is not empty
if ($image)
{
//get the original name of the file from the clients machine
$filename = stripslashes($_FILES['image']['name']);
//get the extension of the file in a lower case format
$extension = getExtension($filename);
$extension = strtolower($extension);
//if it is not a known extension, we will suppose it is an error and will not upload the file,
//otherwise we will do more tests
if (($extension != "jpg") && ($extension != "jpeg") && ($extension != "png"))
{
//print error message
echo '<h1>Nepoznata vrsta fajla!</h1>';
$errors=1;
}
else
{
//get the size of the image in bytes
//$_FILES['image']['tmp_name'] is the temporary filename of the file
//in which the uploaded file was stored on the server
$size=filesize($_FILES['image']['tmp_name']);
//compare the size with the maxim size we defined and print error if bigger
if ($size > MAX_SIZE*1024)
{
echo '<h1>To large file!</h1>';
$errors=1;
}
//we will give an unique name, for example the time in unix time format
$image_name=time().'.'.$extension;
//the new name will be containing the full path where will be stored (images folder)
$newname="Content/Images/".$image_name;
//we verify if the image has been uploaded, and print error instead
//$copied = copy($_FILES['image']['tmp_name'], $newname);
$copied = copy('$_FILES['image']['tmp_name'], $newname);
//echo $_FILES['image']['tmp_name'].'<br/>';
//echo $_FILES['image']['name'];
if (!$copied)
{
echo '<h1>Error occurred!</h1>';
$errors=1;
}}}
//If no errors registred, print the success message
/*if(isset($_POST['Submit']) && !$errors)
{
echo "<h1>You have successfully uploaded image.</h1>";
}*/
?>
我看到一些来自 stackoverflow 的回答者，例如 answers1 和 answer2，但我不知道该怎么做？还有其他建议吗？
谢谢。
【问题讨论】：
-
您应该发布 complete 错误消息，而不仅仅是存根
-
你也应该使用
move_uploaded_file()而不是copy()。 -
我刚刚写了一些东西来覆盖波斯尼亚语的错误信息
-
好吧，用英文写回来。你不明白吗？问这样的问题，你应该发布完整的错误信息。因为 in 包含有关错误的重要信息。
标签： php permissions upload