【发布时间】：2015-03-08 09:23:40
【问题描述】：
我的项目是要找出学生成绩和他们的成绩的平均值、最小值和最大值，但它一直在输出中显示错误。
以下是姓名和等级：
学生：
Alia Nahid Eiman Suad Lamia Salma Mai Wedad Haya Sanaa
测验：
10 20 50 70 80 50 30 90 60 40
期中考试：
30 80 100 40 80 70 70 80 50 30
期末考试：
40 80 70 100 90 60 70 50 40 80
这里是 Java 代码：
package java_final_project;
import java.util.*;
public class Java_Final_Project {
static Scanner console = new Scanner(System.in);
public static void main(String[] args) {
// Declare inputs:
String letter1, letter2, letter3;
int min = Integer.MAX_VALUE;
int max = Integer.MIN_VALUE;
// Declare the four array structures
int[] quiz = new int[10];
int[] midterm = new int[10];
int[] finalexam = new int[10];
String[] students = new String[10];
// Input elements to the arrays
int counter, sum1 = 0;
int sum2 = 0;
int sum3 = 0;
double ave1, ave2, ave3;
int max1, max2, max3;
int min1, min2, min3;
for (counter = 0; counter < 10; counter++) {
System.out.println ("Enter student names and grades of quiz, midterm "
+ "and final with space between them");
students[counter] = console.next();
quiz[counter] = console.nextInt();
sum1 = sum1 + quiz[counter];
midterm[counter]= console.nextInt();
sum2 = sum2 + midterm[counter];
finalexam[counter]= console.nextInt();
sum3 = sum3 + finalexam[counter];
}
ave1 = sum1 / 10;
ave2 = sum2 / 10;
ave3 = sum3 / 10;
// min and max values
max1 = Math.max(quiz[counter], max);
max2 = Math.max(midterm[counter], max);
max3 = Math.max(finalexam[counter], max);
min1 = Math.min(quiz[counter], min);
min2 = Math.min(midterm[counter], min);
min3 = Math.min(finalexam[counter], min);
// if statement for the standing
// ave1
if (ave1 >= 90 && ave1 <= 100) {
letter1 = "E";
} else if (ave1 >= 70 && ave1 <= 80) {
letter1 = "G";
} else if (ave1 >= 50 && ave1 <= 60) {
letter1 = "S";
} else {
letter1 = "P";
}
// ave2
if (ave2 >= 90 && ave2 <= 100) {
letter2 = "E";
} else if (ave2 >= 70 && ave2 <= 80) {
letter2 = "G";
} else if (ave2 >= 50 && ave2 <= 60) {
letter2 = "S";
} else {
letter2 = "P";
}
//ave3
if (ave3 >= 90 && ave3 <= 100) {
letter3 = "E";
} else if (ave3 >= 70 && ave3 <= 80) {
letter3 = "G";
} else if (ave3 >= 50 && ave3 <= 60) {
letter3 = "S";
} else {
letter3 = "P";
}
// Display the elements of the four arrays
System.out.println("Here is the elements of the four arrays");
System.out.println("students" + "\t" + "quiz" + "\t" + "midterm" + "\t" + "finalexam");
for (counter = 0; counter < 10; counter++) {
System.out.println(students[counter] + "\t" + quiz[counter] + "\t" + midterm[counter] + "\t" + finalexam[counter]);
}
System.out.println("Summary Report:");
System.out.println();
System.out.println("students" + "\t" + "\t" + "Quiz" + "\t" + "\t" + "Midterm" + "\t" + "\t" + "FinalExam");
System.out.println();
System.out.println("Average" + "\t" + "\t" + ave1 + "\t" + "\t" + ave2 + "\t" + "\t" + ave3);
System.out.println();
System.out.println("Max" + "\t" + "\t" + max1 + "\t" + "\t" + max2 + "\t" + "\t" + max3);
System.out.println();
System.out.println("Min" + "\t" + "\t" + min1 + "\t" + "\t" + min2 + "\t" + "\t" + min3);
System.out.println();
System.out.println("Standing" + "\t" + "\t" + letter1 + "\t" + "\t" + letter2 + "\t" + "\t" + letter3);
}
}
【问题讨论】：
-
如果您不告诉我们错误是什么，很难帮助您找到它。
-
试试这个。将 max1、max2 和 max3 初始化为整数值。然后： max1 = Math.max(quiz[counter], max1); max2 = Math.max(midterm[counter], max2); max3 = Math.max(finalexam[counter], max3);
-
你应该把它转换成 double ave1 = sum1/10; ave2 = sum2/10； ave3 = sum3/10;
-
你所说的“站立”的东西似乎是以一种非常奇怪的方式计算出来的。这实际上应该是什么意思？
-
它告诉我他们是 max1 、 2 和 3 @DavidWallace 的错误
标签： java arrays max average min