【发布时间】:2013-09-08 16:35:35
【问题描述】:
我有两个应用程序,family 和 person。在Person 类中,我想将可用的mother 和father 选项限制为已经由相同family 创建的对象。如果我可以使用我在person/views.py:PersonCreateview 中设置的get_initial() 中的family_pk,并使用family_pk 来限制mother 和father 的ForeignKey 选择,这似乎是一个很好的方法组逻辑。这可能吗?
family/models.py
class Family(models.Model):
lastname=models.CharField(max_length=100)
def __str__(self):
return self.lastname
family.views.py
from django.views import generic
from django.core.urlresolvers import reverse
from .models import Family
class FamilyListView(generic.ListView):
context_object_name='family_list'
model=Family
class FamilyDetailView(generic.DetailView):
context_object_name='family'
model=Family
pk_url_kwarg='family_pk'
class FamilyCreateView(generic.CreateView):
model=Family
def get_success_url(self,**kwargs):
return reverse('family-detail',kwargs={'family_pk':self.object.pk})
person/models.py
class Person(models.Model):
fields=('family','firstname','mother','father')
family=models.ForeignKey(Family)
firstname=models.CharField(max_length=100)
mother=models.ForeignKey('self',blank=True,null=True)
father=models.ForeignKey('self',blank=True,null=True)
def __str__(self):
return self.firstname
person/views.py
from django.views import generic
from django.core.urlresolvers import reverse
from django.shortcuts import get_object_or_404
from .models import Person
from family.models import Family
class PersonDetailView(generic.DetailView):
model=Person
pk_url_kwarg='person_pk'
class PersonCreateView(generic.CreateView):
model=Person
def get_initial(self):
family=get_object_or_404(Family,pk=self.kwargs.get('family_pk'))
return {'family':family,}
def get_success_url(self,**kwargs):
return reverse('family:family-detail',args=[self.kwargs['family_pk']])
【问题讨论】:
标签: django foreign-keys django-queryset django-class-based-views