对 UITextField 问题使用 UIDatePicker 而不是键盘

Question

您好，我试图在点击UITextField 时显示UIDatePicker 而不是键盘，以便用户可以给出事件的开始和结束时间。我的代码有效，但效果不佳，而且不是我想要的方式。

我的第一个问题是，每当您点击其中一个 UITextField 时，UIDatePicker 只会在第二次点击 UITextField 时出现。否则会显示原来的键盘。

我的第二个问题是，每当编辑 UIDatePicker 时，它只会在编辑 UIDatePicker 时更改 UITextField。我需要UITextField 在打开后立即在UIDatePicker 中显示字符串，以便UITextField 与UIDatePicker 的情况保持同步。

这是我当前的代码：

override func viewDidLoad() {
super.viewDidLoad()
 var datePickerView  : UIDatePicker = UIDatePicker()
    datePickerView.datePickerMode = UIDatePickerMode.Time
    StartTimeTextField.inputView = datePickerView
    datePickerView.addTarget(self, action:
    Selector("handleDatePicker:"), forControlEvents: UIControlEvents.ValueChanged)

    var datePickerView2  : UIDatePicker = UIDatePicker()
    datePickerView2.datePickerMode = UIDatePickerMode.Time
    EndTimeTextField.inputView = datePickerView2
    datePickerView2.addTarget(self, action: Selector("handleDatePicker2:"), forControlEvents: UIControlEvents.ValueChanged)
    }

func handleDatePicker(sender: UIDatePicker) {
    var dateFormatter = NSDateFormatter()
    dateFormatter.dateFormat = "hh mm am pm"
    StartTimeTextField.text = dateFormatter.stringFromDate(sender.date)
}



func handleDatePicker2(sender: UIDatePicker) {
    var dateFormatter = NSDateFormatter()
    dateFormatter.dateFormat = "hh mm am pm"
    EndTimeTextField.text = dateFormatter.stringFromDate(sender.date)
}

谁能帮帮我？谢谢

Answer 1

为什么你要通过动作来改变键盘！

只需在viewDidLoad 中添加您的代码：

var datePickerView  : UIDatePicker = UIDatePicker()
datePickerView.datePickerMode = UIDatePickerMode.Time
StartTimeTextField.inputView = datePickerView
datePickerView.addTarget(self, action: Selector("handleDatePicker:"), forControlEvents: UIControlEvents.ValueChanged)

var datePickerView  : UIDatePicker = UIDatePicker()
datePickerView.datePickerMode = UIDatePickerMode.Time
EndTimeTextField.inputView = datePickerView
datePickerView.addTarget(self, action: Selector("handleDatePicker2:"), forControlEvents: UIControlEvents.ValueChanged)

并删除像

这样的方法

@IBAction func