Swift 自定义键盘 - 在键盘长按时显示额外的字母弹出？

Question

我的应用中有一个使用 swift 开发的自定义键盘扩展。他们的键盘工作正常。我想添加在长按键盘按钮（如默认 iOS 键盘）时显示带有额外字符的弹出窗口的功能。像这样的：

我搜索了很多，但大多数都没有回答，回答的都在 Obj-C 中。我对 Obj-C 了解不多，而且对 swift 编程也很陌生。

我已经看过this、this 和this。但这些都没有多大帮助。

任何帮助将不胜感激。

Answer 1

1.在您的视图上添加按钮
（这只是为了向您展示）

let btn: UIButton=UIButton(frame: CGRect(x: 5, y: 70, width: 30, height: 30))
     btn.setTitle("A", for: .normal)
    btn.setTitleColor(UIColor.black, for: .normal);
     self.view.addSubview(btn)

2。在您的按钮上添加长按手势

     let longGesture = UILongPressGestureRecognizer(target: self, action: #selector(longPress(sender:)))
longGesture.minimumPressDuration = 1.2
        btn.addGestureRecognizer(longGesture)

3。处理长按手势,

您可以添加 PopUpView 并在其上添加一些按钮，

⚠️ 注意：你有多个按钮，所以你必须检查 From CGPoint 在哪个按钮上被点击了

  func longPress( sender: Any) {
            
            let longPressGesture = sender as! UILongPressGestureRecognizer

//Only run this code When State Begain
if longPressGesture.state != UIGestureRecognizerState.Began {
            return
     }
// if PopUpView is Already in added than remove and than  add
 if let checkView = self.view.viewWithTag(1001) as? UIView {
         // remove popView
        popUpView .removeFromSuperview()
   }
            
            let tapLocation = longPressGesture.location(in: self.view)
            
            
            popUpView=UIView(frame: CGRect(x: tapLocation.x-10, y: tapLocation.y-65, width: 150, height: 60))
            popUpView.backgroundColor=UIColor.orange
            popUpView.layer.cornerRadius=5
            popUpView.layer.borderWidth=2
            popUpView.tag=1001
            popUpView.layer.borderColor=UIColor.black.cgColor
            
            let btn0: UIButton=UIButton(frame: CGRect(x: 5, y: 5, width: 30, height: 30))
            btn0.setTitle("A1", for: .normal)
            btn0.setTitleColor(UIColor.black, for: .normal);
            btn0.layer.borderWidth=0.5
            btn0.layer.borderColor=UIColor.lightGray.cgColor
            
            popUpView.addSubview(btn0)
            
            let btn1: UIButton=UIButton(frame: CGRect(x: 35, y: 5, width: 30, height: 30))
            btn1.setTitle("A2", for: .normal)
            btn1.setTitleColor(UIColor.black, for: .normal);
            btn1.layer.borderWidth=0.5
            btn1.layer.borderColor=UIColor.lightGray.cgColor
            
            popUpView.addSubview(btn1)
            
            let btn2: UIButton=UIButton(frame: CGRect(x: 70, y: 5, width: 30, height: 30))
            btn2.setTitle("A2", for: .normal)
            btn2.setTitleColor(UIColor.black, for: .normal);
            btn2.layer.borderWidth=0.5
            btn2.layer.borderColor=UIColor.lightGray.cgColor
            
            popUpView.addSubview(btn2)
            
            btn0.addTarget(self, action: #selector(self.buttonAction(sender:)),
                             for: UIControlEvents.touchUpInside)
            btn1.addTarget(self, action: #selector(self.buttonAction(sender:)),
                           for: UIControlEvents.touchUpInside)
            btn2.addTarget(self, action: #selector(self.buttonAction(sender:)),
                           for: UIControlEvents.touchUpInside)
     
             self.view.addSubview(popUpView)
            
           
        }

4.处理额外的按钮按下

（Do your Stuff here add remove popUpView from SuperView）

      func buttonAction( sender: Any) {
            
            // Do your Stuff Here
            
            
            //Than remove popView
            popUpView .removeFromSuperview()
        }

结果 ✅

✅ 注意：您可以使用UIBezierPath 绘制自定义形状的 PopUpView

Answer 2

您应该使用 LongPress 识别器。请检查此以获取更多详细信息。 Long press delete key of a custom keyboard in swift

Answer 3

这很简单，按照这个步骤来完成这个任务

• 打开您的主故事板
• 选择要显示多个字母的 TextField。
• 从屏幕右侧打开属性检查器
• 向上滚动并在Min font size 下方查找capitalization
• 将capitalization设置为单词
• 设置所有其他默认值，主要是keyboard type 现在构建并运行它并检查字母s、e 等。