如何在pynput中监控鼠标双击？

Question

在监控过程中双击时遇到问题。“谁能给我一个代码，如何使用pynput在python中监控鼠标双击？”

Answer 1

当您想同时获得single click 时，没有简单的方法获得double click。

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要控制double click（不控制single click），您可以记住previous click 的时间并与current click 进行比较。如果差异是即。 0.3s 则可以将其视为double click。

代码只用于左键

from pynput.mouse import Listener, Button
import time

previous_left = 0

def on_click(x, y, button, pressed):
    global previous_left
    
    #text = 'Pressed' if pressed else 'Released'
    #print('{0} {1} at {2}'.format(text, button, (x, y)))

    double_click_left = False
    
    # double click left button
    if pressed and button == Button.left:
        current_left = time.time()
        
        diff_left = current_left - previous_left
        print('diff left:', diff_left)
        
        if diff_left < 0.3:
            print('double click left')
            double_click_left = True
            
        previous_left = current_left
    
    # other code
    
    if double_click_left:
        # Stop listener
        return False

with Listener(on_click=on_click) as listener:
    # ... some code ...
    listener.join()

其他按钮的代码类似

from pynput.mouse import Listener, Button
import time

previous_left = 0
previous_right = 0
previous_middle = 0

def on_click(x, y, button, pressed):
    global previous_left
    global previous_right
    global previous_middle
    
    #text = 'Pressed' if pressed else 'Released'
    #print('{0} {1} at {2}'.format(text, button, (x, y)))

    double_click_left = False
    double_click_right = False
    double_click_middle = False
    
    # double click left button
    if pressed and button == Button.left:
        current_left = time.time()
        
        diff_left = current_left - previous_left
        print('diff left:', diff_left)
        
        if diff_left < 0.3:
            print('double click left')
            double_click_left = True
            
        previous_left = current_left
    
    # double click right button
    if pressed and button == Button.right:
        current_right = time.time()
        
        diff_right = current_right - previous_right
        print('diff right:', diff_right)
        
        if diff_right < 0.3:
            print('double click right')
            double_click_right = True
            
        previous_right = current_right

    # double click middle button
    if pressed and button == Button.middle:
        current_middle = time.time()
        
        diff_middle = current_middle - previous_middle
        print('diff middle:', diff_middle)
        
        if diff_middle < 0.3:
            print('double click middle')
            double_click_middle = True
            
        previous_middle = current_middle

    # other code
    
    if double_click_left:
        # Stop listener
        return False


with Listener(on_click=on_click) as listener:
    # ... some code ...
    listener.join()

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但问题是当您还想控制单击时，因为它会在第一次单击后运行某些功能 0.3s，以通知您不是双击而是单击 - 它需要线程 Timer 或者它需要运行其他一直循环运行的线程将当前时间与previous_left 进行比较，如果在previous_left 之后0.3s 没有点击，则将其视为单击。

我没有这种情况的例子。