石墨烯 Python 列表为所有字段解析 null

Question

我在 python 中使用 GraphQL 正在尝试解析列表数据，但字段解析为 null。我怎样才能让他们返回实际的列表数据？

这是我的代码的 sn-p

import graphene


class User(graphene.ObjectType):
    """ Type definition for User """
    id = graphene.Int()
    username = graphene.String()
    email = graphene.String()

class Query(graphene.ObjectType):
    users = graphene.List(User)

    def resolve_users(self, args):
        resp = [{'id': 39330, 'username': 'RCraig', 'email': 
                 'WRussell@dolor.gov', 'teamId': 0}, {'id': 39331, 
                 'username': 'AHohmann','email': 'AMarina@sapien.com', 
                 'teamId': 0}]
        return  resp

schema = graphene.Schema(query=Query)

可以在graphene playground测试sn-p

这是我当前的查询

以及不受欢迎的响应

Answer 1

您需要返回用户的对象，而不仅仅是字典：

import graphene


class User(graphene.ObjectType):
    """ Type definition for User """
    id = graphene.Int()
    username = graphene.String()
    email = graphene.String()

class Query(graphene.ObjectType):
    users = graphene.List(User)

    def resolve_users(self, args):
        resp = [User(id=39330, username='RCraig', email='WRussell@dolor.gov')]
        return  resp

schema = graphene.Schema(query=Query)

您可以签入playground。