Django REST Framework：嵌套序列化程序未出现

Question

我在使用嵌套序列化程序和 Django 休息框架时遇到问题。 将 serializer_class 设置为“UserSerializer”时，“NameSerializer”类中的嵌套数据不会出现。 但是，当我将 serializer_class 设置为“NameSerializer”时，数据确实出现了。

使用UserSerializer时API返回：

HTTP 200 OK
Allow: GET, POST, HEAD, OPTIONS
Content-Type: application/json
Vary: Accept

[
  {
    "id": 1,
    "userName": "admin@admin.com"
  },
  {
    "id": 2,
    "userName": "2@admin.com"
  },
  {
    "id": 3,
    "userName": "3@admin.com"
  },
  {
    "id": 4,
    "userName": "4@admin.com"
  }
]

我希望它返回什么：

HTTP 200 OK
Allow: GET, POST, HEAD, OPTIONS
Content-Type: application/json
Vary: Accept

[
  {
    "id": 1,
    "userName": "admin@admin.com"
    "name": {
      "familyName": "Joe",
      "givenName": "admin",
      "formated": "admin Joe"
    },
  },
  {
    "id": 2,
    "userName": "jane@admin.com"
    "name": {
      "familyName": "Doe",
      "givenName": "Jane",
      "formated": "Jane Doe"
    },
  },
  {
    "id": 3,
    "userName": "Billy@admin.com"
    "name": {
      "familyName": "Idol",
      "givenName": "Billy",
      "formated": "Billy Idol"
    },
  },
  {
    "id": 4,
    "userName": "User@admin.com"
    "name": {
      "familyName": "B",
      "givenName": "User",
      "formated": "User B"
    },
  }
]

views.py

from API.models import Person
from API.serializers import *
from rest_framework import viewsets

class UserViewSet(viewsets.ModelViewSet):
   queryset = Person.objects.all()
   serializer_class = NameSerializer

models.py

class Person(AbstractBaseUser):
    email = models.EmailField(
       verbose_name='email address',
       max_length=255,
       unique=True,
       )
    first_name = models.CharField(max_length=254, blank=True)
    last_name =  models.CharField(max_length=254, blank=True)

serializers.py

class NameSerializer(serializers.ModelSerializer):

  familyName = serializers.CharField(source='last_name')
  givenName = serializers.CharField(source='first_name')
  formatted = serializers.SerializerMethodField()

  class Meta:
      model = Person
      fields = ('familyName', 'givenName', 'formatted',)


  def get_formatted(slef, obj):
      FullName = obj.first_name + '' + obj.last_name
      return FullName


class UserSerializer(serializers.ModelSerializer):

  name = NameSerializer(many=True, readonly=True)
  userName = serializers.EmailField(source='email')

  class Meta:
      model = Person
      fields = ('id', 'userName', 'name')

感谢任何帮助

Answer 1

您不需要创建NameSerializer 序列化程序。在UserSerializer 中为name 字段创建一个方法字段如：

class UserSerializer(serializers.ModelSerializer):

    userName = serializers.EmailField(source='email')
    name = serializers.SerializerMethodField()

    class Meta:
        model = Person
        fields = ('id', 'userName', 'name')

    def get_name(self, obj):
        name = {
            'familyName': obj.first_name,
            'givenName': obj.last_name,
            'formatted': obj.first_name + ' ' + obj.last_name
        }
        return name

它会给你想要的结果。

Answer 2

这可能会对您有所帮助：

class UserSerializer(serializers.ModelSerializer): name = NameSerializer() userName = serializers.EmailField(source='email')

     class Meta:
         model = Person
         fields = ('id', 'userName', 'name')

如果项目应该是一个列表，那么只需要传递many=True。

Answer 3

也许尝试使用SerializerMethodField： 像这样的：

class UserSerializer(serializers.ModelSerializer):

    userName = serializers.EmailField(source='email')
    name = serializers.SerializerMethodField()

    class Meta:
        model = Person
        fields = ('id', 'userName', 'name')

    def get_name(self, obj):
        return {
            'familyName': obj.first_name,
            'givenName': obj.last_name,
            'formatted': obj.first_name + ' ' + obj.last_name
        }