【发布时间】:2020-12-15 03:56:14
【问题描述】:
让我创建一个用例来讨论。
CREATE DATABASE sample;
USE sample;
CREATE TABLE quote (
`id` int(2) unsigned NOT NULL AUTO_INCREMENT,
`code` text ,
`date` date DEFAULT NULL,
`close` double DEFAULT NULL,
PRIMARY KEY (`id`)
) ;
INSERT INTO quote (`code`, `date`, `close`)
VALUES ('epm', '20200824', 2.64);
INSERT INTO quote (`code`, `date`, `close`)
VALUES ('dss', '20200824', 6.4);
使用 sqlalchemy 只执行一个 sql 命令很简单。
import pandas as pd
from sqlalchemy import create_engine
user = 'root'
mysql_pass = 'your mysql passwd'
mysql_ip = '127.0.0.1'
engine = create_engine("mysql+pymysql://{}:{}@{}:3306".format(user,mysql_pass,mysql_ip))
cmd_one_line_sql = 'select * from sample.quote;'
df = pd.read_sql_query(cmd_one_line_sql,con = engine)
df
id code date close
0 1 epm 2020-08-24 2.64
1 2 dss 2020-08-24 6.40
我得到了想要的结果,现在cmd包含多个sql命令,为简单起见,它只包含两行
cmd_multi_lines_sql = 'use sample;select * from quote;'
cmd_multi_lines_sql 只是将cmd_one_line_sql 拆分为两个。
我按照手册重写了代码sn-p:
execute many sql commands with sqlalchemy
import pandas as pd
from sqlalchemy import create_engine
user = 'root'
mysql_pass = 'your mysql passwd'
mysql_ip = '127.0.0.1'
engine = create_engine("mysql+pymysql://{}:{}@{}:3306".format(user,mysql_pass,mysql_ip))
connection = engine.raw_connection()
cmd_multi_lines_sql = 'use sample;select * from quote;'
try:
cursor = connection.cursor()
cursor.execute(cmd_multi_lines_sql)
results_one = cursor.fetchall()
finally:
connection.close()
获取以下错误信息:
Traceback (most recent call last):
File "<stdin>", line 3, in <module>
File "/usr/local/lib/python3.5/dist-packages/pymysql/cursors.py", line 170, in execute
result = self._query(query)
File "/usr/local/lib/python3.5/dist-packages/pymysql/cursors.py", line 328, in _query
conn.query(q)
File "/usr/local/lib/python3.5/dist-packages/pymysql/connections.py", line 517, in query
self._affected_rows = self._read_query_result(unbuffered=unbuffered)
File "/usr/local/lib/python3.5/dist-packages/pymysql/connections.py", line 732, in _read_query_result
result.read()
File "/usr/local/lib/python3.5/dist-packages/pymysql/connections.py", line 1075, in read
first_packet = self.connection._read_packet()
File "/usr/local/lib/python3.5/dist-packages/pymysql/connections.py", line 684, in _read_packet
packet.check_error()
File "/usr/local/lib/python3.5/dist-packages/pymysql/protocol.py", line 220, in check_error
err.raise_mysql_exception(self._data)
File "/usr/local/lib/python3.5/dist-packages/pymysql/err.py", line 109, in raise_mysql_exception
raise errorclass(errno, errval)
pymysql.err.ProgrammingError: (1064, "You have an error in your SQL syntax; check the manual that corresponds to your MariaDB server version for the right syntax to use near 'select * from quote' at line 1")
再试一次:
vim /tmp/test.sql
use sample;
select * from quote;
#write the commands in `/tmp/test.sql`
f = open('/tmp/test.sql','r')
cmd = f.read()
df = pd.read_sql_query(cmd, con = engine)
它输出相同的错误信息。如何修复它?
【问题讨论】:
-
如果您没有编辑收到的错误消息,那么您的 cmd 变量(或文本文件)显然包含“此处的 cmd 命令”字符串。如果你编辑了它,不知道sql错误是什么,很难帮助你。
标签: mysql python-3.x sqlalchemy pymysql