生成随机数并检查重复项

Question

我想知道是否有一种简单的方法可以检查六个不同随机数之间的重复项。我想检查 6 个随机数中的 4 个以上是否相同以创建 if 语句。

例如；

let firstRandomNumber = arc4random_uniform(3) + 1
let secondRandomNumber = arc4random_uniform(3) + 1
let thirdRandomNumber = arc4random_uniform(3) + 1
let fourthRandomNumber = arc4random_uniform(3) + 1
let fifthRandomNumber = arc4random_uniform(3) + 1
let sixthRandomNumber = arc4random_uniform(3) + 1

使用这些随机数，如果其中四个或更多相同（例如3, 3, 3, 3, 2, 1），我想执行和操作。有人知道怎么做吗？

Answer 1

这里有一个更简短的解决方案：

let numbers      = [3, 3, 2, 3, 2, 3]

let counts       = numbers.map({ (N) in numbers.filter({ $0 == N }).count })
let fourOrMore   = counts.contains({ $0 >= 4 })

if fourOrMore  { print(" there are more than four identical values") }

还有一个更短的：

let numbers      = [3, 3, 2, 3, 2, 3]

if numbers.contains({ (N) in numbers.filter({$0 == N}).count >= 4 })
{ print(" there are more than four identical values") }

Answer 2

这个呢

let allValues = [firstRandomNumber,secondRandomNumber, thirdRandomNumber, fourthRandomNumber,fifthRandomNumber, sixthRandomNumber]

let maxOccurrencies:(value:UInt32, times:Int)? = allValues
    .reduce([UInt32:Int]()) { (var dict, elm) -> [UInt32:Int] in
        dict[elm] = (dict[elm] ?? 0) + 1
        return dict
    }
    .maxElement { $0.1 < $1.1 }


if let (value, times) = maxOccurrencies where times >= 4 {
    print("The value \(value) does appear \(times) times")
}