【发布时间】:2012-12-27 22:19:55
【问题描述】:
我创建了一个整数数组,并想从中选择一个随机元素。我该怎么做?
【问题讨论】:
标签: arrays visual-studio-2008 vba random
我创建了一个整数数组,并想从中选择一个随机元素。我该怎么做?
【问题讨论】:
标签: arrays visual-studio-2008 vba random
YourArray(New Random().Next(0,YourArray.Length-1))
或者为了更清楚而分开:
Dim Rand as New Random()
Dim Index as Integer = Rand.Next(0, YourArray.Length - 1)
Dim SelectedValue = YourArray(Index)
【讨论】:
在0 到Len-1 的范围内创建一个随机整数,其中Len 是数组的长度。要生成随机整数,请使用 Random 类的实例。
DIM rand As New Random
DIM idx as rand.Next(0, Len)
REM Now you can pick an element idx from the array
REM to get a random element.
DIM res as myArray(index)
【讨论】:
Rnd可以得到[0,1),然后再乘以你的arraylength,你可以得到[0,YourArrayLength)之间的数
Randomize
Int(array.length* Rnd)
【讨论】:
只想说接受的答案不正确。
这是正确的
Dim Rand as New Random()
Dim Index as Integer = Rand.Next(0, YourArray.Length)
Dim SelectedValue = YourArray(Index)
为什么?
因为最大值是独占的。因此,如果您不想在 3 个元素中进行选择,例如,最大值应该是 3,而不是 2。
'
' Summary:
' Returns a non-negative random integer.
'
' Returns:
' A 32-bit signed integer that is greater than or equal to 0 and less than System.Int32.MaxValue.
Public Overridable Function [Next]() As Integer
'
' Summary:
' Returns a random integer that is within a specified range.
'
' Parameters:
' minValue:
' The inclusive lower bound of the random number returned.
'
' maxValue:
' The **exclusive** upper bound of the random number returned. maxValue must be greater
' than or equal to minValue.
'
' Returns:
' A 32-bit signed integer greater than or equal to minValue and **less than** maxValue;
' that is, the range of return values includes minValue but not maxValue. If minValue
' equals maxValue, minValue is returned.
'
' Exceptions:
' T:System.ArgumentOutOfRangeException:
' minValue is greater than maxValue.
【讨论】: