快速调用复杂字典（关联数组）上的过滤器

Question

我有这个数组：

class Filter {

    var key = ""
    var value = ""

    init(key: String, value: String) {
        self.key = key
        self.value = value
    }

}

let arry = [
    "a":[Filter(key:"city",value:"aachen"),Filter(key:"city",value:"augsburg")],
    "b":[Filter(key:"city",value:"bremen"),Filter(key:"city",value:"berlin")]
]

我想查找奥格斯堡并使用过滤器功能将其从字典中删除，因此输出如下所示：

let arry = [
    "a":[Filter(key:"city",value:"aachen")],
    "b":[Filter(key:"city",value:"bremen"),Filter(key:"city",value:"berlin")]
]

我尝试了很多过滤器和地图星座，但我总是得到这个结构：

let arry = [
    ["a":[Filter(key:"city",value:"aachen")]],
    ["b":[Filter(key:"city",value:"bremen"),Filter(key:"city",value:"berlin")]]
]

例如使用此过滤器：

arry.map({ key,values in

    return [key:values.filter{$0.value != "augsburg"}]
})

这里有什么问题？如何过滤和映射更复杂的对象？

Answer 1

也许你应该知道的一件事是Dictionary 的map 方法返回Array，而不是Dictionary。

public func map<T>(_ transform: (Key, Value) throws -> T) rethrows -> [T]

因此，如果您希望过滤后的结果为Dictionary，则可能需要使用reduce：

class Filter: CustomStringConvertible {

    var key = ""
    var value = ""

    init(key: String, value: String) {
        self.key = key
        self.value = value
    }

    //For debugging
    var description: String {
        return "<Filter: key=\(key), value=\(value)>"
    }
}

let dict = [
    "a":[Filter(key:"city",value:"aachen"),Filter(key:"city",value:"augsburg")],
    "b":[Filter(key:"city",value:"bremen"),Filter(key:"city",value:"berlin")]
]

let filteredDict = dict.reduce([:]) {tempDict, nextPair in
    var mutableDict = tempDict
    mutableDict[nextPair.key] = nextPair.value.filter {$0.value != "augsburg"}
    return mutableDict
}

（通常，Swift Dictionary 是关联数组的基于哈希表的实现，但您最好避免将 arry 命名为 Dictionary 变量。这样的命名非常混乱。）

或者简单地使用for-in循环：

var resultDict: [String: [Filter]] = [:]
for (key, value) in dict {
    resultDict[key] = value.filter {$0.value != "augsburg"}
}
print(resultDict) //->["b": [<Filter: key=city, value=bremen>, <Filter: key=city, value=berlin>], "a": [<Filter: key=city, value=aachen>]]