【发布时间】:2017-07-11 10:02:46
【问题描述】:
我正在开发一个程序,该程序可以解析日志文件并返回 IP 地址和其他一些内容的热门点击。目前我遇到了麻烦,我无法将这个问题的任何答案解释为我现在正在做的事情。这是我所有的代码:
import gzip
from collections import Counter
logFileName = open('C:\\Users\\Pawlaczykm\\Desktop\\fileNames.txt', 'r')
ipAdd = []
landingPages = []
ALL_ipAdd = []
ALL_landingPages = []
# everything after this line gets done to all files
for line in logFileName.readlines():
# rstrip removes a blank line from output
# print 'Summary of: ' + line.rstrip()
# use gzip to decompress the file
with gzip.open('C:\\Users\\Pawlaczykm\\Desktop\\logFiles\\' + line.rstrip() + '.gz', 'rb') as f:
# we extract the ip addresses in lines 15-18
for eachLine in f:
parts = eachLine.split('\t')
if len(parts) > 1:
ipAdd.append(parts[2])
ALL_ipAdd.append(ipAdd)
# use gzip to decompress the file
with gzip.open('C:\\Users\\Pawlaczykm\\Desktop\\logFiles\\' + line.rstrip() + '.gz', 'rb') as f:
# we extract the landing pages
for eachLine in f:
parts = eachLine.split('\t')
if len(parts) > 1:
variable = parts[8].split('?')[0]
landingPages.append(variable)
v): (-v, k))[:10]
ALL_landingPages.append(landingPages)
ALL_ipAddDict = dict(Counter(ALL_ipAdd).most_common())
sortedALL_ipAdd = sorted(ALL_ipAddDict.iteritems(), key=lambda (k, v): (-v, k))[:10]
print 'Top IPs of all files'
print(sortedALL_ipAdd)
ALL_LandingPageDict = dict(Counter(ALL_landingPages).most_common())
sortedALL_LandingPage = sorted(ALL_LandingPageDict.iteritems(), key=lambda (k, v): (-v, k))[:10]
print 'Top landing pages of all files'
print (sortedALL_LandingPage)
现在我遇到问题的地方是以下行:
ALL_ipAddDict = dict(Counter(ALL_ipAdd).most_common())
我运行整个程序时的输出是这样的:
Traceback (most recent call last):
File "C:/Users/Pawlaczykm/PycharmProjects/LogParse/parseText.py", line 35, in <module>
ALL_ipAddDict = dict(Counter(ALL_ipAdd).most_common())
File "C:\Python27\lib\collections.py", line 477, in __init__
self.update(*args, **kwds)
File "C:\Python27\lib\collections.py", line 567, in update
self[elem] = self_get(elem, 0) + 1
TypeError: unhashable type: 'list'
有人可以帮助我吗?这令人沮丧。
【问题讨论】:
-
列表是可变的,因此不可散列。因此它们不能用作字典中的键
-
你能告诉我们
ALL_ipAdd里面有什么吗? -
@Ev.Kounis 有没有办法可以获取一个列表,将其转换为字典,然后对字典进行哈希处理?
-
@mattp341 您可以在将
list用作字典键之前将其转换为tuple -
@StevenRumbalski 鉴于
All_ipAdd中只有一个列表,该解决方案仅适用于第一个切片{key:val for key, val in Counter(ALL_ipAdd[0]).most_common()}
标签: python list dictionary hashable