获取 shell 脚本中的行

Question

我正在尝试获取所有“ RESP：0，成功；”在行中-输入命令：RESP：0，成功；-这是我的代码。我将如何处理？

**for i in {2..4}
do 
   date  
   CMDCount="CMD"$i
   eval CMD="$"$CMDCount
   echo "server CMD "${CMD}""${CMDCount}"";
   echo "" 
   (sleep 1;echo $login;
    sleep 1;echo ${CMD};
    sleep 1;echo $logout;sleep 1)|telnet localhost 9685
    sleep 1

done**

输出如下：

server CMD xxxxxxxxxxxxxxxxxxxxxxxxxxxxCMD2

Trying 127.0.0.1...
Connected to localhost.
Escape character is '^]'.
CONNECTING TO xxx...
PROCESS CPL CONNECTED...
Enter command:RESP:0,sucess;
Enter command:
Enter command: 
Enter command:Connection closed by foreign host.
Sat Aug  3 12:18:21 CST 2013
server CMD xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxCMD3

Trying 127.0.0.1...
Connected to localhost.
Escape character is '^]'.
CONNECTING TO xxx...
PROCESS CPL CONNECTED...
Enter command:RESP:0,sucess;
Enter command:
Enter command: 
Enter command:Connection closed by foreign host.
Sat Aug  3 12:18:26 CST 2013
server CMD xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx;CMD4

Trying 127.0.0.1...
Connected to localhost.
Escape character is '^]'.
CONNECTING TO xxx...
PROCESS CPL CONNECTED...
Enter command:RESP:0,sucess;
Enter command:
Enter command: 
Enter command:Connection closed by foreign host.

Answer 1

您可能会发现这些链接很有用：

• String Manipulation
• Regular Expressions

而且，要从整个字符串中提取响应部分，您可以使用以下内容：

echo `expr "${CMD}" : '\.*?(RESP)(:)(\\d)\'`