python和whatsapp的问题

Question

我将whatsapp中的数据提取到一个txt文件中 我需要在输出文件中创建 4 列日期、时间、名称和消息

import pandas as pd

# read file by lines
with open('D:\Analysis\example_chat_whatsapp.txt', encoding="utf-8") as f: 
     data=f.readlines()


# # sanity stats
print('num lines: %s' %(len(data)))

# parse text and create list of lists structure
# remove first whatsapp info message
dataset = data[1:]
cleaned_data = []
for line in dataset:
# grab the info and cut it out
    date = line.split(" ")[0]
    line2 = line[len(date):]
    time = line2.split(" ")[0][:2]
    line3 = line2[len(time):]
    name = line3.split(":")[0][:4]
    line4 = line3[len(name):]
    message = line4[6:-1] # strip newline charactor

    #print(date, time, name, message)
cleaned_data.append([date, time, name, message])

  
#Create the DataFrame 
df = pd.DataFrame(cleaned_data, columns = ['Date', 'Time', 'Name', 'Message']) 
df

我遇到的问题是变量时间（空）和名称输出错误。 日期和消息没有问题，有预期的输出

Answer 1

如果未注释 print(date, time, name, message) 打印有效数据，则只需在 cleaned_data.append([date, time, name, message]) 前添加 4 个空格。

for line in dataset:
    # grab the info and cut it out
    date = line.split(" ")[0]
    line2 = line[len(date) + 1:]
    time = line2.split(" ")[0]
    line3 = line2[len(time):]
    name = line3.split(":")[0]
    line4 = line3[len(name):]
    message = line4
    
    row = (date[1:], time[:-1], name[1:], message[2:-1])
    # print("'%s', '%s', '%s', '%s'" % row)
    cleaned_data.append(row)

s[1:] 返回 s 并删除第一个字符，s[:-1] 返回 s 并删除最后一个字符，依此类推。