如何从 API 获取数据 - php - curl

Question

如何从 api url 获取数据（图片）？

API 结果：

info = { "title" : "aaaaa", "image" : "bbbbb" };

API 网址：

http://www.example.com/api

代码：

<?php
$ch = curl_init();
curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, false);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_URL, 'http://www.example.com/api');
$result = curl_exec($ch);
curl_close($ch);
$obj = json_decode($result);
echo $result->image;
?>

Array
(
    [curlResult] => info = { "title" : "aaaaa", "image" : "bbbbb" };
    [info] => Array
        (
            [url] => http://127.0.0.1/api.txt
            [content_type] => text/plain
            [http_code] => 200
            [header_size] => 237
            [request_size] => 55
            [filetime] => -1
            [ssl_verify_result] => 0
            [redirect_count] => 0
            [total_time] => 0
            [namelookup_time] => 0
            [connect_time] => 0
            [pretransfer_time] => 0
            [size_upload] => 0
            [size_download] => 48
            [speed_download] => 48
            [speed_upload] => 0
            [download_content_length] => 48
            [upload_content_length] => 0
            [starttransfer_time] => 0
            [redirect_time] => 0
            [certinfo] => Array
                (
                )

            [primary_ip] => 127.0.0.1
            [primary_port] => 80
            [local_ip] => 127.0.0.1
            [local_port] => 61662
            [redirect_url] => 
        )

    [errno] => 0
    [error] => 
)

Answer 1

尝试调试此问题的一个好方法是检查 curl 信息数组或 curl 错误。

<?php
/**
 * Handles making a cURL request
 *
 * @param string $url         URL to call out to for information.
 * @param bool   $callDetails Optional condition to allow for extended       
 *   information return including error and getinfo details.
 *
 * @return array $returnGroup cURL response and optional details.
 */
function makeRequest($url, $callDetails = false)
{
  // Set handle
  $ch = curl_init($url);

  // Set options
  curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, false);
  curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);

  // Execute curl handle add results to data return array.
  $result = curl_exec($ch);
  $returnGroup = ['curlResult' => $result,];

  // If details of curl execution are asked for add them to return group.
  if ($callDetails) {
    $returnGroup['info'] = curl_getinfo($ch);
    $returnGroup['errno'] = curl_errno($ch);
    $returnGroup['error'] = curl_error($ch);
  }

  // Close cURL and return response.
  curl_close($ch);
  return $returnGroup;
}

$url = /* some url */
$response = makeRequest($url, true);

// Check your return to make sure you are making a successful connection.
echo '<pre>';
print_r($response);
?>

看看你是否成功地建立了连接，以及你在响应中得到的确切信息，应该让你更好地了解如何处理它。

编辑

似乎有一些非 JSON 字符串数据阻止了 json_decode 函数工作。这不太理想，但它确实发生了。在这种特定情况下，以下方法应该会有所帮助，但这只是涉及不良数据问题的一种解决方法。

// continuing from above :) formatted for readability

/**
 * Separates JSON string from unnecessary data, parses into
 * an object and returns.
 *
 * @param string $curlResult String returned from cURL call.
 *
 * @return object $jsonObject Parsed JSON object. 
 */
function cleanJsonString($curlResult) {
  // Separates result string into array at " = ".
  $responseChunks = explode(" = ", $curlResult);

  // Removes semicolon from end of JSON string.
  $jsonString = substr($responseChunks[1], -1);

  // Parse JSON string into object.
  $jsonObject = json_decode($jsonString);

  return $jsonObject;
}

// Clean result.
$jsonObject = cleanJsonString($response['curlResult']);

// Print image object property.
echo $jsonObject->image;

Answer 2

取决于图像是实际的 blob 内容还是 url 链接可能会改变您显示图像的方式。

如果是内容，您需要获取 MIME 类型才能正确显示，以便设置正确的页眉。

如果链接，请访问该网页。

Answer 3

使用DOMDocument获取图片url

   $ch = curl_init();
    curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, false);
    curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
    curl_setopt($ch, CURLOPT_URL, 'http://www.halalfoodrecipe.com/recipe/index');
    $result = curl_exec($ch);
    curl_close($ch);
    $obj = json_decode($result);

    $dom = new DOMDocument;
    $dom->loadHTML($result);

    foreach ($dom->getElementsByTagName('img') as $img) {
        echo $img->getAttribute('src');
    }

Answer 4

在你的 api 中：

1. 将整个图像内容读入字符串。 (file_get_contents)
2. 将其编码为 base64 字符串。 (base64_encode)
3. 将其添加到返回结果中。 （替换“图像”=“bbbbb”）

这看起来：

$result = array(
    "title" => "aaaaa",
    "image" => "bbbbb"
);
$result["image"] = file_get_contents("path/to/your/image/file");
$result["image"] = base64_encode($result["image"]);
$result = json_encode($result);
header("Content-Type: application/json");
echo $result;

在你的代码中：

$ch = curl_init();
curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, false);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_URL, 'http://www.example.com/api');
$result = curl_exec($ch);
curl_close($ch);
$obj = json_decode($result);
// Do it if you encoded image string
$image_string = base64_decode($obj->image);
// Create image from base 64 decoded string
$image = imagecreatefromstring($image_string);
// And save your image as desired type (png or jpeg)
imagepng($image, "path/to/save/your/image/as/png");

编辑：您是否可以提供服务器端代码。您的代码按预期工作，问题出在哪里？