【发布时间】:2016-02-14 02:00:51
【问题描述】:
我想将视频(从图库中选择)上传到服务器(localhost-Wampserver 在我的计算机上运行 Apache 2.4.4)。从异常和搜索中,我发现网络操作不应该发生在运行 UI 的线程中。但我该怎么做呢?我的代码如下:
PostFile:
public final class PostFile
{
public static final MediaType MEDIA_TYPE_MARKDOWN
= MediaType.parse("vide/mp4");
private final OkHttpClient client = new OkHttpClient();
public void run(String path) throws Exception
{
File file = new File(path);
Request request = new Request.Builder()
.url("http://192.168.1.7")
.post(RequestBody.create(MEDIA_TYPE_MARKDOWN, file))
.build();
Response response = client.newCall(request).execute();
if (!response.isSuccessful()) throw new IOException("Unexpected code " + response);
System.out.println(response.body().string());
}
}
MainActivity.java:
public class MainActivity extends Activity
{
private static int RESULT_LOAD_IMG = 1;
String decodableString;
@Override
protected void onCreate(Bundle savedInstanceState)
{
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
}
public void loadImagefromGallery(View view)
{
// Create intent to Open Image applications like Gallery, Google Photos
Intent galleryIntent = new Intent(Intent.ACTION_PICK,
android.provider.MediaStore.Video.Media.EXTERNAL_CONTENT_URI);
// Start the Intent
startActivityForResult(galleryIntent, RESULT_LOAD_IMG);
}
@Override
protected void onActivityResult(int requestCode, int resultCode, Intent data)
{
super.onActivityResult(requestCode, resultCode, data);
try {
// When a video is picked
if (requestCode == RESULT_LOAD_IMG && resultCode == RESULT_OK
&& null != data)
{
// Get the video from data
Uri selectedVideo = data.getData();
String[] filePathColumn = { MediaStore.Video.Media.DATA };
Cursor cursor = getContentResolver().query(selectedVideo,
filePathColumn, null, null, null);
cursor.moveToFirst();
int columnIndex = cursor.getColumnIndex(filePathColumn[0]);
decodableString = cursor.getString(columnIndex);
Log.i("mok",decodableString);
cursor.close();
new PostFile().run(decodableString);
Log.i("mok","done");
} else
{
Toast.makeText(this, "You haven't picked any video",
Toast.LENGTH_LONG).show();
}
} catch (Exception e)
{
e.printStackTrace();
Toast.makeText(this, "Something went wrong", Toast.LENGTH_LONG)
.show();
}
}
}
【问题讨论】:
-
下次不要截图错误。只需复制它并像代码一样粘贴。它更容易阅读。
-
@DamianKozlak 我不知道如何在 logcat 中(一次全部)复制它们
-
用鼠标选择它... :)
-
@DamianKozlak 相信我这是不可能的。是一行一行的。我有这么多使用鼠标的专业知识;)
标签: java android multithreading exception retrofit