将 [Future<Object,Error>] 转换为 Future<[Object],Error>

Question

有什么方法可以解析下面的代码并将其值作为数组 Future 返回。我正在使用BrightFutures 未来实现

return apiService.getArrayObject()
   .flatMap(NetworkQueue.context) { (arrayObjects: [ArrayObject]) -> Future<[Object], Error> in
      let objects = arrayObjects.map {
         apiService.getObject(of: $0.objectId)
      }
      return objects // ERROR since objects is [Future<Object,Error>] rather than needed output
    }

Answer 1

使用顺序

   return apiService.getArrayObject()
      .flatMap(NetworkQueue.context) { (arrayObjects: [ArrayObject]) -> Future<[Object], Error> in
          let objects: [Future<Object, Error>] = arrayObjects.map {
              apiService.getObject(of: $0.objectId)
          }
          let sequenceFuture: Future<[Object], NoError> = objects
                    .sequence()

         return sequenceFuture
    }