【发布时间】:2014-02-24 01:42:56
【问题描述】:
我正在使用 Apache Tomcat,我想将数据发送到 http 服务器并从 HTTP 服务器(来自 servlet)获取响应。
问题:
当我使用HTTP客户端发送数据时,似乎没有传递数据(发送的参数没有被servlet显示)。当我通过 HTTP 浏览器 (Chrome) 进行模拟时,一切似乎都正常。
下面是我的 servlet 和我的 http 客户端的示例。
我的 HTTP Servlet:
public class MyServlet extends HttpServlet {
public void doGet(HttpServletRequest req, HttpServletResponse res)
throws ServletException, IOException {
PrintWriter out = res.getWriter();
out.println("This ervlet requires POST but received GET");
out.close();
}
protected void doPost(HttpServletRequest request,
HttpServletResponse response) throws ServletException, IOException {
response.setContentType("text/html");
PrintWriter out = response.getWriter();
for (String name : request.getParameterMap().keySet()) {
out.write("PARAMETER :" + name);
out.write("\n");
}
for (Part name : request.getParts()) {
out.write("MULTIPART PARAMETER :" + name.getName());
out.write("\n");
}
String p1 = request.getParameter("input1");
out.write("RECEIVED PARAMETER:" + p1);
out.write("\n");
out.close();
}
}
我的 HTTP 客户端
/**
* Example how to use multipart/form encoded POST request.
*/
public class ClientMultipartFormPost {
public static void main(String[] args) throws Exception {
CloseableHttpClient httpclient = HttpClients.createDefault();
try {
HttpPost httppost = new HttpPost("http://example.com:8080" +
"/myservlet");
FileBody bin = new FileBody(new File("file1.txt"));
StringBody comment = new StringBody("A binary file of some kind", ContentType.TEXT_PLAIN);
HttpEntity reqEntity = MultipartEntityBuilder.create()
.addPart("bin", bin)
.addPart("input1", comment)
.build();
httppost.setEntity(reqEntity);
System.out.println("executing request " + httppost.getRequestLine());
CloseableHttpResponse response = httpclient.execute(httppost);
try {
System.out.println("----------------------------------------");
System.out.println(response.getStatusLine());
HttpEntity resEntity = response.getEntity();
if (resEntity != null) {
PrintWriter sWriter = new PrintWriter(System.out);
IOUtils.copy(resEntity.getContent(), sWriter, "UTF-8");
sWriter.close();
}
EntityUtils.consume(resEntity);
} finally {
response.close();
}
} finally {
httpclient.close();
}
}
}
输出:执行请求 POST
http://example.com:8080/myservletHTTP/1.1
---------------------------------------- HTTP/1.1 200 OK
接收参数:空
浏览器客户端(测试) 浏览器 POST 按预期工作:
<form name="input" action="http://example.com:8080/servlet" method="post">
<input type="text" name="input1">
<input type="submit" value="Submit">
</form>
输出:参数:输入1
收到的参数:AAAAAAAAA
更新: 浏览器代码:
Request URL:http://localhost:8080/servlet
Request Method:POST
Status Code:200 OK
Request Headersview parsed
POST /LyticsRemote/flexi HTTP/1.1
Host: localhost:8080
Connection: keep-alive
Content-Length: 10
Cache-Control: max-age=0
Accept: text/html,application/xhtml+xml,application/xml;q=0.9,image/webp,*/*;q=0.8
Origin: null
User-Agent: Mozilla/5.0 (Windows NT 6.1; WOW64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/32.0.1700.102 Safari/537.36
Content-Type: application/x-www-form-urlencoded
Accept-Encoding: gzip,deflate,sdch
Accept-Language: cs,en-GB;q=0.8,en;q=0.6
Cookie: JSESSIONID=9BD73E186BC8A081AB87C8EF58483523
Form Dataview sourceview URL encoded
input1:aaa
Response Headersview source
Content-Length:41
Content-Type:text/html;charset=ISO-8859-1
Date:Fri, 31 Jan 2014 11:46:54 GMT
Server:Apache-Coyote/1.1
【问题讨论】:
-
比较浏览器和HttpClient发送的headers。
-
请问如何显示http headers?
-
您可以使用 WireShark (wireshark.org) 之类的工具来查看 HttpClient 的标头。那些来自 Chrome 的更容易看到:点击 F12 键,单击网络选项卡,然后将表单发送到您的 servlet 以查看标题。
-
嗯,很遗憾,我无法在 Windows 平台上进行环回捕获:-/
标签: java http tomcat servlets client