Python套接字等待客户端连接

Question

有没有办法在客户端连接到该服务器之前停止 while 循环？ 服务器应该为每个新的客户端连接创建一个新线程，有可能吗？

import socket
import threading

def clientdialog(myS):
    conn, addr = myS.accept()
    print ("Connection from: " + str(addr))

    while 1:
                data = conn.recv(1024).decode("utf-8")
                if not data or data == 'q':
                    break
                print ("from connected  user: " + str(data))

host = "192.168.1.3"
port = 1998

mySocket = socket.socket()
mySocket.bind((host,port))

while True:

    mySocket.listen(10)
    #whait until socket don't connect

    try:
        threading._start_new_thread(clientdialog, (mySocket))
    except:
        print("error starting thread")

Answer 1

socket.listen 函数将被调用一次，因为它设置了连接队列的大小。

另一个名为socket.accept 的函数将阻塞，直到建立连接。像这样修改你的代码：

mySocket = socket.socket()
mySocket.bind((host,port))
mySocket.listen(10)

while True:
    client_socket, client_address = mySocket.accept() # blocking call
    .... # do something with the connection

如需更多信息，请访问docs。

此外，您还想将客户端套接字的详细信息传递给线程。不需要服务器套接字。实际上，是这样的：

def handle_client(client_socket, client_address):
    .... # do something with client socket
    client_socket.close()

...

while True:
    client_socket, client_address = mySocket.accept()
    T = threading.Thread(target=handle_client, args=(client_socket, client_address))
    T.start()

您在主循环中接受连接，然后将客户端详细信息传递给线程进行处理。