【问题标题】:Python Client-Server how to handle timeoutPython客户端-服务器如何处理超时
【发布时间】:2020-06-09 21:32:59
【问题描述】:

我有一个 TCP 客户端-服务器,客户端向服务器发送 shell 命令,服务器以所述命令的输出进行响应。某些命令(例如 date 或 cd )不起作用,因为我假设它们是交互式的,而我的代码无法处理它。每当我发送所述命令时,我的客户端似乎挂起,只是说发送......而我的服务器从未收到任何东西。

我想弄清楚如何在可能出现超时的情况下处理这个问题,如果发送命令的时间超过 5 秒,客户端将导致超时或简单地处理它并打印一条消息,说明命令没有在保持客户端连接到服务器的同时成功执行。

这是我的代码

客户:

import socket


# Client
sock = socket.socket(socket.AF_INET, socket.SOCK_STREAM)  # creates TCP Socket

# local host and port
LOCAL_HOST = '127.0.0.1'

PORT = 5313
BUFFER_SIZE = 5000  # size of message

sock.settimeout(5)

# connect socket to ip and port
sock.connect((LOCAL_HOST, PORT))
print("Connected to server\n")
print("Enter quit to close connection\n")
while True:

    message = input("Please enter a command:\n")  # ask user to input message
    if message == 'quit':
        break
    if len(message) == 0:
        print("Please enter something")
        message = input("Please enter a command:\n")
    print("Sending %s" % message)
    sock.send(str.encode(message))  # send message
    command = str(sock.recv(BUFFER_SIZE), "utf-8")  # receive message

    print("received %s" % command)
print("closing connection with server")
sock.close()

服务器:

import socket
import subprocess


# Server
# Some commands do not work such as cd. Date does not work on windows because it is interactive.

# creates TCP socket
sock = socket.socket(socket.AF_INET, socket.SOCK_STREAM)

sock.settimeout(5)

# port and server ip(localhost)
LOCAL_HOST = ''
PORT = 5313

BUFFER_SIZE = 5000  # size of message

# test connection
print("Server starting up on %s with port number %s" % (LOCAL_HOST, PORT))
# bind socket to ip and port
sock.bind((LOCAL_HOST, PORT))
# listen to socket
sock.listen(1)

# socket will accept connection and client address

print("Waiting for connection")  # waiting for connection
connection, address = sock.accept()  # accept connection with client address
print("Connected to", address)  # connected by address
while True:

    command = connection.recv(BUFFER_SIZE)  # receive message from client

    if not command:
        break

    if len(command) > 0:

        terminal = subprocess.Popen(command[:].decode("utf-8"), shell=True, stdout=subprocess.PIPE,
                                    stderr=subprocess.PIPE, stdin=subprocess.PIPE)
        output = terminal.stdout.read() + terminal.stderr.read()
        output_as_string = str(output, "utf-8")
        connection.send(str.encode("0:") + str.encode(output_as_string))
        print(output_as_string)

print("Closing Server")
sock.close()
connection.close()

【问题讨论】:

    标签: python sockets tcp subprocess client-server


    【解决方案1】:

    有多种方法可以做到,但可能最简单的方法是调用subprocess.check_output() 方法,它允许您指定以秒为单位的超时值,并且还返回子进程生成的文本,即:

    [...]
    
    while True:
        command = connection.recv(BUFFER_SIZE)  # receive message from client
        if not command:
            break
        command = command.decode("utf-8").strip()
        if len(command) > 0:
            try:
               output_as_string = subprocess.check_output(command, stderr=subprocess.STDOUT, shell=True, timeout=5.0).decode("utf-8")
            except subprocess.TimeoutExpired:
               output_as_string = "Sub-process timed out!\r\n"
    
            connection.send(str.encode("0:") + str.encode(output_as_string))
    
    [...]
    

    【讨论】:

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