【发布时间】:2018-03-21 13:07:09
【问题描述】:
我正在尝试编写一个将产生以下输出的过程
exec WinOrLose(4)
Welcome to the Win or Lose Game. Your number is 4.
You win.
You lose.
You win.
You lose.
==> You lose!
到目前为止,我有这个:
CREATE or REPLACE Procedure WinOrLose (
p_choice number ) AS
v_answer number;
DECLARE
v_answer := p_choice
BEGIN
dbms_output.put_line ('Welcome to the Win or Lose Game. Your number is ' ||
v_answer);
FOR v_answer in 1..10
IF MOD(v_answer, 2) = 0 THEN -- v_answer is even
dbms_output.put_line (You lose)
END;
/
我不确定从那里去哪里。我的思考过程(伪代码)是这样的:
SET v_answer := 1
While Loop (outside)
MOD(v_answer,2) = 0 then dbms.output (YOU LOSE)
ELSE
dbms.output (YOU WIN)
end if;
v_answer := p_choice
【问题讨论】:
-
规则是什么?查看代码和伪代码没有任何意义。
标签: sql if-statement plsql while-loop oracle10g