【发布时间】:2017-02-18 03:54:24
【问题描述】:
如果之前没有点击过按钮,我会在 PHP while 循环中输出这个 jQuery 表单,如果有,则只是一个带有值的图像,该功能就像 facebook 一样的按钮,当用户点击按钮时,图标更改,因此不再可单击,并且值增加 1。表单提交有效,但我似乎无法在不影响提要中的所有其他按钮和值的情况下更新提要中的图标图像和值计数……我尝试了 jQuery @987654321 @ 但它会替换提要中的所有 #bumpCont div……
index.php
<div class="images">
<?php
while($row = $result2->fetch_assoc()){
$path = $row['path'];
$user = $row['user'];
$id = $row['id'];
$desc = $row['desc'];
$update = $row['update_date'];
$bump = $row['bump'];
$timeFirst = strtotime($date);
$timeSecond = strtotime($update);
$timeSecond = $timeSecond + 86400;
$timer = $timeSecond - $timeFirst;
?>
<?php if(empty($desc)){}else{?><div id="desc"><?php echo $desc;?></div><?php }?>
<img id="pic" src="uploads/<?php echo $path;?>"/>
<div id="userCont">
<div id="user"><a rel="external" href="user_profile.php?user='.$user.'"><?php echo $user;?></a></div>
<div id="timer"><?php echo $timer;?></div>
<?php
if(in_array($path, $mypath)) {
echo '<div id="bumpCont"><img id="bump" style="height:55px;right:8px;top: 2px;position: relative;" src="../img/bumpg.png"/><span id="bumpCount">'.$bump.'</span></div>';
}else{
echo '<form method="post" id="bumpF" data-ajax="false">';
echo '<input name="id" data-ajax="false" id="field_'.$id.'" type="hidden" value="'.$id.'" />';
echo '<div id="bumpCont"><input type="image" style="height:55px;right:8px;top: 2px;position: relative; " id="bump" src="../img/bump.png" id="searchForm" onclick="SubmitForm('.$id.');" value="Send" /><span id="bumpCount">'.$bump.'</span></div>';
echo ' </form>';
}
?>
</div>
<?php
}
?>
//Submit Form
function SubmitForm(id) {
event.preventDefault();
var name = $('#field_'+id).val();
console.log(name);
$.post("bump.php", {name: name},
function(data) {
$( "#bumpCont" ).replaceWith( '<div id="bumpCont"><img id="bump" style="height:55px;right:8px;top: 2px;position: relative;" src="../img/bumpg.png"/><span id="bumpCount">' + data + '</span></div>' );
}
Bump.php -
$id = $_POST['name'];
$sessionUser = $_SESSION['userSession'];
// GET USERNAME
$sql = "SELECT * FROM userbase WHERE user_id='$sessionUser'";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
while($row = $result->fetch_assoc()) {
$myname = $row['username'];
}
}
$bump = 1;
$sql = "SELECT * FROM images WHERE id=$id";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
while($row = $result->fetch_assoc()) {
$bump = $row['bump'];
$path = $row['path'];
$desc = $row['desc'];
$post_user = $row['user'];
$bump++;
}
}
$bumpC = 0;
$sql = "SELECT * FROM bumped WHERE path='$path' AND myname ='$myname'";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
while($row = $result->fetch_assoc()) {
$bumpC++;
}
}
echo $bump;
if($bumpC >= 1){
}else{
$sql = "INSERT INTO `bumped` ( `myname`,`path`, `description`, `post_user`) VALUES ( '$myname','$path', '$desc', '$post_user')";
if ($conn->query($sql) === TRUE) {
} else {
echo "Error: " . $sql . "<br>" . $conn->error;
}
$sql = "UPDATE images SET update_date='$date' WHERE id=$id";
if ($conn->query($sql) === TRUE) {
} else {
echo "Error updating record: " . $conn->error;
}
$sql = "UPDATE images SET bump=$bump WHERE id=$id";
if ($conn->query($sql) === TRUE) {
} else {
echo "Error updating record: " . $conn->error;
}
}
【问题讨论】:
-
你能解释一下你的问题吗?
-
你的 replaceWith() 代码在哪里?
-
当然,我希望 #bumpCount 的 span id 在提交到作为 echo $bump 的 bump.php 后更新为新值。我希望重新加载整个bumpCont div以反映被点击的按钮,因此图像也会改变以反映点击......当然不重新加载页面:-)我删除了replaceWith(),因为它不起作用所以我是打开不同的方法,但我会把它放回去展示我的例子..
-
我知道您有多个元素在循环中,并且基于对特定元素的点击,您只想更改该特定元素的内容,我在下面向您展示了一个示例。
标签: javascript php jquery while-loop replacewith