如何跳转到代码的开头？ [关闭]

Question

我正在制作一个要求用户输入的程序。如果用户输入输入，它将显示为输入，然后完成程序。如何让程序从头开始？ 我的代码是这样构建的：（只显示构建而不是代码本身）

please enter user input:
while (x != y)
{ 
    if ( x == y )
    { 
        printf("printing something");
    }
    else if (x > y )
    {
        printf("printing something");
    }
    else
    {
        printf("printing something");
    }
}

Answer 1

int main(void)
{
    int num = 0;
    while( 1 )
    {
        printf("This is a game to find the password. Start this game by trying to guess it with numbers from 1 - 100. The program will tell you if you are close or not.\n");

        num = 0; // reset the num back to zero
        while (num != 65)
        {
            printf("please enter a number:\n");
            num = GetInt();

            if (num == 65)
            {
                printf("Nice!!\n");
                break; // exit the while (num != 65)
            }
            else if (num > 50 && num < 60 )
            {
                printf("almost there! go higher!\n");

            }
        }
    }
}

Answer 2

如果你不介意使用goto:

HERE: please enter user input:
while (x!= y)
{ 
    if ( x == y )
    { 
        printf("printing something");
    }
    else if (x > y )
    {
        printf("printing something");
    }
    else
    {
        printf("printing something");
    }
    goto HERE;
}

然而，在这个例子中，你可以看到你永远不会中断。您必须谨慎使用
goto。

编辑：

上面的代码有错误。为了进入while循环x!=y。但是后来
你检查x==y，它总是false。所以：

HERE: please enter user input:  
while (true)
{ 
    if ( x == y )
    { 
        printf("printing something");
        break;
    }
    else if (x > y )
    {
        printf("printing something");
    }
    else
    {
        printf("printing something");
    }
    goto HERE;
}

编辑 2：

你只有 一个 while 循环

int num;

//your code here

HERE:
num = GetInt();
while(true)
{
   if (num == 65)
   {
       printf("Nice!!\n");
       break;
   }
   else if (num > 50 && num < 60 )

   }
   else if (something )
       something
   }
   .
   .
   .
   else{
       something
   }
   goto HERE;
}

变态