Python文本框仅在循环完成后更新

Question

我有一个很长的自动化程序，它使用很长的 WHILE 循环。随着过程的进行，我希望能够更新文本框中的文本。但是，根据我所做的研究，这似乎是不可能的，并且当 WHILE 循环完成时，所有结果都会立即“转储”。这对我没用。

如果文本框可以随着 SHELL 的更新而更新，我会很高兴，因为它与实际过程同步。

我制作了一个简单的 TEST 文件，看看我是否可以让它工作。以下是 TEST 文件的代码：

from tkinter import *
import time
import tkinter as tk
import tkinter.font as tkFont  

root=Tk()
myFont = tkFont.Font(family = 'Helvetica', size = 18, weight = 'bold')
text_cell_bg="cyan"        #TEXT CELL BACKGROUND COLOR
text_cell_fg="black"       #TEXT CELL TEXT COLOR
text_cell_height=2         #TEXT CELL HEIGHT
text_cell_width=30         #TEXT CELL WIDTH
button_bg="blue"           #BUTTON CELL BACKGROUND COLOR
button_fg="white"          #BUTTON CELL TEXT COLOR
button_height=2            #BUTTON CELL HEIGTH
button_width=10            #BUTTON CELL WIDTH

textbox=Text(root)
textbox.insert(END, 'Default Text\n\n')


def count_print ():
    count = 0
    letter = "A"
    while count < 5:
        print("Count = ",count,".  Letter = ",letter,".")
        textbox_value = "Count = {}.  Letter = {}.\n".format(count,letter)
        textbox.insert(1.0, textbox_value)
        count += 1
        time.sleep(1)

textbox.pack()

button1=tk.Button(root, text='output', command=count_print, font = myFont,
                        height=button_height,
                        width=button_width,
                        bg = button_bg,
                        fg = button_fg)
button1.pack()

root.mainloop()

Answer 1

您可以使用 Tkinter 从函数本身内部调用您的函数。 Tkinter 对此有一个特殊的功能。

from tkinter import *
import time
import tkinter as tk
import tkinter.font as tk_font

root = Tk()
myFont = tk_font.Font(family='Helvetica', size=18, weight='bold')
text_cell_bg = "cyan"  # TEXT CELL BACKGROUND COLOR
text_cell_fg = "black"  # TEXT CELL TEXT COLOR
text_cell_height = 2  # TEXT CELL HEIGHT
text_cell_width = 30  # TEXT CELL WIDTH
button_bg = "blue"  # BUTTON CELL BACKGROUND COLOR
button_fg = "white"  # BUTTON CELL TEXT COLOR
button_height = 2  # BUTTON CELL HEIGHT
button_width = 10  # BUTTON CELL WIDTH

textbox = Text(root)
textbox.insert(END, 'Default Text\n\n')


def count_print(n_times=0): # tell your function how many times you have called it
(on the first call this will be 0)
    n = n_times + 1
    letter = "A"
    if n <= 5:
        print("Count = ", n, ".  Letter = ", letter, ".")# you can change the n var on these lines to n_times if you want 0-4 rather than printing 1-5.
        textbox_value = "Count = {}.  Letter = {}.\n".format(n, letter)
        textbox.insert(1.0, textbox_value)
        root.after(1000, count_print, n) # this number replaces and time.sleep  it's set to 1 second right now it also call the count_print function passing n as a variable


textbox.pack()

button1 = tk.Button(root, text='output', command=count_print, font=myFont,
                    height=button_height,
                    width=button_width,
                    bg=button_bg,
                    fg=button_fg)
button1.pack()

root.mainloop()

我希望这会有所帮助。另外，我不会在我的项目中使用 Tkinter，而且我也绝对不是很擅长使用它，所以我对 root 的了解要归功于我。在得到这个答案之后， Make Tkinter force a "refresh" a text widget in mid-command?