有没有办法将近似值输出到列表中？

Question

我正在尝试编写一个使用巴比伦平方根方程的代码（python），通过使用 while 循环来近似平方根，直到误差小于 epsilon 值，并且我试图以 [x1] 的形式打印近似值,x2,x3...] 但只设法让近似值在单独的行上垂直向下列出

例如

x1

x2

x3

到目前为止，这是我的代码。我是编码新手，所以任何帮助和建议将不胜感激:)

a= float(input('enter the positive value that you wish to find the babylonian square root of '))
e= float(input('enter a positive value for maxium error '))
x= float(input('enter an arbitrary starting value '))

if a<0 or a==0:
    print(' a must be a positive number')
elif e<0 or e==0:
    print('e must be a positive number')
elif x==0:
    print('starting value cannot be 0 as cant divide by 0!')
else:
 
    
    while abs(x**2-a)>e or abs(x**2-a)==e :
        x=0.5*(x-(a/x))
        xn=0.5*(x-(a/x))
         x=xn 
   
        print(x)

Answer 1

创建一个列表，然后输出该列表：

a = float(input('enter the positive value that you wish to find the babylonian square root of '))
e = float(input('enter a positive value for maxium error '))
x = float(input('enter an arbitrary starting value '))

if a < 0 or a == 0:
    print(' a must be a positive number')
elif e < 0 or e == 0:
    print('e must be a positive number')
elif x == 0:
    print('starting value cannot be 0 as cant divide by 0!')
else:
    result_list = []
    while abs(x ** 2 - a) > e or abs(x ** 2 - a) == e:
        x = 0.5 * (x - (a / x))
        xn = 0.5 * (x - (a / x))
        x = xn
        result_list.append(x)
    print(result_list)