在使用 webhook.site 的电子邮件上需要提取 XPath 帮助

Question

我需要从进入我的 webhook.site 网址的原始电子邮件中提取特定行。我认为这将是一个 xpath 提取或一些自定义操作，但我的知识仅限于此。 我需要提取：主题：这是关于内容类型的标题：文本/纯文本。 我这样做的路径和布局是什么？ 谢谢

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From: leadnotification-noreply2@ylopo.com
Date: Wed, 27 Oct 2021 12:21:33 -0700
Message-ID: <CAN2r-3o0aD_98y2GrdxdBW7W6UHi8RMS9-JmvsHrftheurwMeQ@mail.gmail.com>
Subject: Ylopo Priority Alert - Party: Daniel Askew 19293 -
 PRIORITY_LEAD_EVENT - massaquoimartha@yahoo.com - 8562838525
To: OsirsYlopoPriorityEmail@email.webhook.site, qojfsghi@mailparser.io
Content-Type: multipart/alternative; boundary="00000000000084f8be05cf5a80dc"

--00000000000084f8be05cf5a80dc
Content-Type: text/plain; charset="UTF-8"

Lead Name: Martha Mansaray
Lead Email: massaquoimartha@yahoo.com
Lead Phone: 8562838525
Text:

Ylopo PRIORITY LEAD ALERT: Martha Mansaray (856) 283-8525

Martha Mansaray VIEWED 6185 Old Highway 31E, Bethpage, TN
<https://andrea.livetn.com/listing-detail/124037148> 29 TIMES.

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Answer 1

我认为您需要正则表达式，因为 XPath 用于从 XML/HTML 类型的文本中查找节点。但是正则表达式可以用于任何文本。要获取标题名称“主题”的值，您可以使用正则表达式\nSubject: (.*)。

Python 示例：

import re
sample = """
...
<text you want to parse>
...
Subject: Ylopo Priority Alert - Party: Daniel Askew 19293 -
"""
if match := re.search(r"\nSubject: (.*)", sample):
    print(match.group(1))  # output: Ylopo Priority Alert - Party: Daniel Askew 19293 -