SQL Server 全文搜索 - 获取总字段值

Question

假设我有下表“Addresses”：

+----+-------------+---------------+------------------+
| ID | CompanyName |    Street     |     City         |
+----+-------------+---------------+------------------+
|  1 | Salvador    | Hollywood 123 | Paradise City    |
|  2 | Zer0        | Avenue 34     | Opportunity City |
+----+-------------+---------------+------------------+

如果我进行全文搜索，例如：

SELECT * FROM Addresses WHERE CONTAINS(*, 'Salv')

能不能回来

• 列的名称，其中包含建立的值（在本例中为“CompanyName”）
• 列的完整值，其中包含建立值（在本例中为“Salvador”

Answer 1

我可以建议：

 SELECT 
      *,
      CASE WHEN CONTAINS(CompanyName, 'Salv') THEN 'CompanyName'
           WHEN CONTAINS(Street, 'Salv') THEN 'Street'
           WHEN CONTAINS(City, 'Salv') THEN 'City'
      END As ColumnName,
      CASE WHEN CONTAINS(CompanyName, 'Salv') THEN CompanyName
           WHEN CONTAINS(Street, 'Salv') THEN Street
           WHEN CONTAINS(City, 'Salv') THEN City
      END As FullText
 FROM Addresses 
 WHERE CONTAINS(*, 'Salv')