List<object>.Contains 表达式树

Question

我想构建一个等同于预期的表达式...

Expression<Func<ReferencedEntity, bool>> expected = (ReferencedEntity referencedEntity) => foreignKeys.Contains(referencedEntity.Id);
Expression<Func<ReferencedEntity, bool>> actual;

foreignKeys 类型是List<object>

这是我目前所拥有的，我认为它会使用 Expression.Call() 方法，但不确定如何去做。

ParameterExpression entityParameter = Expression.Parameter(typeof(TReferencedEntity), "referencedEntity");
MemberExpression memberExpression = Expression.Property(entityParameter, "Id");
Expression convertExpression = Expression.Convert(memberExpression, typeof(object)); //This is becuase the memberExpression for Id returns a int.

//Expression containsExpression = Expression.Call(????

//actual = Expression.Lambda<Func<TReferencedEntity, bool>>(????, entityParameter);

感谢您的帮助。

Answer 1

如果没有塞缪尔的建议，这是我无法完成的解决方案......

    /// <summary>
    /// 
    /// </summary>
    /// <param name="foreignKeys"></param>
    /// <returns></returns>
    private Expression<Func<TReferencedEntity, bool>> BuildForeignKeysContainsPredicate(List<object> foreignKeys, string primaryKey)
    {
        Expression<Func<TReferencedEntity, bool>> result = default(Expression<Func<TReferencedEntity, bool>>);

        try
        {
            ParameterExpression entityParameter = Expression.Parameter(typeof(TReferencedEntity), "referencedEntity");
            ConstantExpression foreignKeysParameter = Expression.Constant(foreignKeys, typeof(List<object>));
            MemberExpression memberExpression = Expression.Property(entityParameter, primaryKey);
            Expression convertExpression = Expression.Convert(memberExpression, typeof(object));
            MethodCallExpression containsExpression = Expression.Call(foreignKeysParameter
                , "Contains", new Type[] { }, convertExpression);

            result = Expression.Lambda<Func<TReferencedEntity, bool>>(containsExpression, entityParameter);

        }
        catch (Exception ex)
        {
            throw ex;
        }

        return result;
    }

Answer 2

我不知道解决方案，但我知道您如何获得它。创建一个接受 Expression<Func<ReferencedEntity, bool>> 的虚拟函数并将其传递给您的 lambda。并且使用调试器，您可以检查编译器如何为您创建表达式。