Python转义sys argv中的特殊字符

Question

我有一个使用 sys.argv 的脚本，并且输入可能包含特殊字符（分号）。我只需要输入字符串，但分号会搞砸一切..

我有：

def myscript(text)
    print text


a = myscript(sys.argv[1])
print a

我试试：

>>  python script.py "With these words she greeted Prince Vasili Kuragin, a man of high rank and importance, who was the first to arrive at her reception. Anna Pavlovna had had a cough for some days. She was, as she said, suffering" from la grippe; grippe being then a new word in St. Petersburg""

我明白了：

'With these words she greeted Prince Vasili Kuragin, a man of high rank and importance, who was the first to arrive at her reception. Anna Pavlovna had had a cough for some days. She was, as she said, suffering'
None
bash: grippe: command not found

我只想将整个字符串放入脚本中，不管里面是什么..

我试过了：

a = myscript(repr(sys.argv[1]))
a = myscript(str(sys.argv[1]))

Answer 1

这不是python的问题，您需要在调用shell中对其进行转义。只需将引号转义为\"，将分号转义为\;。

$ python testme.py "With these words she greeted Prince Vasili Kuragin, a man of high rank and importance, who was the first to arrive at her reception. Anna Pavlovna had had a cough for some days. She was, as she said, suffering\" from la grippe; grippe being then a new word in St. Petersburg\""

With these words she greeted Prince Vasili Kuragin, a man of high rank and importance, who was the first to arrive at her reception. Anna Pavlovna had had a cough for some days. She was, as she said, suffering" from la grippe; grippe being then a new word in St. Petersburg"

Answer 2

这不是 python 问题，而是 bash 问题。 Bash 认为;（分号）正在分隔一个新的 bash 命令。你需要逃避它。