【发布时间】:2016-10-01 02:05:14
【问题描述】:
我正在尝试在 Unix 上通过 Java 运行 SQL*Loader。
我正在使用以下命令,当我在命令行 (bash) 上运行它时它可以工作:
sqlldr userid=user/pass@\"\(DESCRIPTION = \(SDU = xxxx\) \(TDU = xxxx\) \(ADDRESS_LIST = \(ADDRESS = \(PROTOCOL = TCP\)\(HOST = xxxxx\)\(PORT = xxxx\)\) \(LOAD_BALANCE = on\) \(FAILOVER = on \) \)\(CONNECT_DATA = \(SERVICE_NAME = xxxx\) \)\)\" control='xxxx' log='xxxx' readsize=xxxx streamsize=xxxx
我正在使用转义来run it without a tnsnames.ora file。
这就是我在 Java 代码中的翻译方式:
String unixCmd = "sqlldr userid=user/pass@\\\"\\(DESCRIPTION = \\(SDU = xxxx\\) \\(TDU = xxxx\\) \\(ADDRESS_LIST = \\(ADDRESS = \\(PROTOCOL = TCP\\)\\(HOST = xxxx\\)\\(PORT = xxxx\\)\\) \\(LOAD_BALANCE = on\\) \\(FAILOVER = on \\) \\)\\(CONNECT_DATA = \\(SERVICE_NAME = xxxx\\) \\)\\)\\\" control='xxxx' log='xxxx' readsize=xxxx streamsize=xxxx";
System.out.println(unixCmd);
p = Runtime.getRuntime().exec(unixCmd);//not working
p = Runtime.getRuntime().exec("sh -c "+unixCmd);//not working
我收到以下错误消息:
LRM-00116: syntax error at 'user/pass' following '='
SQL*Loader: Release 11.2.0.2.0 - Production on Wed Jun 1 11:29:59 2016
Copyright (c) 1982, 2009, Oracle and/or its affiliates. All rights reserved.
我做错了什么?
【问题讨论】:
标签: java oracle bash escaping sql-loader