从具有特定值的行中减去

Question

我在物化视图中从 10 个不同的表中创建了一个表。

部分是这样的

group_name	value1	value2
group1	100	20
group2	200	40
unknown	300	60
TOTAL	600	120

我必须将值 group_name = 'unknown' 的行中的所有值重新排列到其他行。决赛桌应该是这样的

group_name	value1	value2
group1	200	40
group2	400	80
TOTAL	600	120

所以“group1”的公式是：

 unknown x group1 x (TOTAL-unknown) + group1

表格是用大量代码创建的，请注意 - 它不是我写的，它是给我的，我必须使用它。我不喜欢它的样子，所以请不要生气。无论如何，查询看起来像这样：

TABLESPACE pg_default
AS
 WITH table_value1 AS (
         SELECT 
            table1.group_name,
            table1.value1,
           FROM table1
        ), table_value2 AS (
         SELECT 
            table2.group_name,
            table2.value2,
           FROM table2
        ), TOTAL_groups AS (
         SELECT 
            'value1'::text AS group_name,
             sum(xy_table."value1")::numeric as results
           FROM xy_table
        UNION ALL
         SELECT 
            'value2'::text AS group_name,
             sum(xy_table."value2")::numeric as results
           FROM xy_table
        UNION ALL
         SELECT 
            'unknown'::text AS group_name,
             sum(xy_table."unknown")::numeric as results
           FROM xy_table
        ), TOTAL AS (
         SELECT 
            TOTAL_groups.group_name,
            TOTAL_groups.results
            FROM TOTAL_groups
        UNION ALL           
            'TOTAL'::text AS group_name,
            round(sum(TOTAL_groups.raba), 1) as results
           FROM skupaj_energenti
        )
 SELECT 
    a.group_name,
    COALESCE(a.results, 0::numeric) AS value1,
    COALESCE(a.results, 0::numeric) AS value2
  FROM table_value1 a
     LEFT JOIN table_value2 b ON b.group_name = a.group_name
     LEFT JOIN TOTAL c ON f.group_name = a.group_name
WITH DATA;

我不知道我应该如何在 SQL 中编写这样的条件。请帮忙。

Answer 1

将“未知”行分配给其他行。假设 value1, value2 是 DECIMAL

select group_name, value1 * (1 + k1) value1, value2 * (1 + k2) value2
from tbl
cross join (
    select sum(case group_name when 'unknown' then value1 end) / sum(case group_name when 'TOTAL' then value1 else -value1 end)  k1,
           sum(case group_name when 'unknown' then value2 end) / sum(case group_name when 'TOTAL' then value2 else -value2 end)  k2
    from tbl
    where group_name in ('TOTAL', 'unknown')
    ) t
where tbl.group_name not in ('TOTAL', 'unknown')

db<>fiddle