如何仅从包含 Oracle SQL 中特定字符串的列中选择和别名数据

Question

我正在处理 Oracle 数据库中的地址记录。每行包含有关两个父母的信息。电话号码类型有四列，数字有四列。类型为 Other_No_Type_1、Other_No_Type_2、Other_No_Type_3、Other_No_Type_4，其中任何一个都可能包含“Name1:Mobile”、“Name2:Mobile”、“Father Work”或“Mother Work”的值，该值指的是数字在下一列（Other_No_1、Other_No_2、Other_No_3 或 Other_No_4）。当 Other_No_Type_x 等于 Name1:Mobile 并将其别名为“contact_1_mobile”并提取 Name2:Mobile 并将其别名为“contact_2_mobile”时，我需要提取 Other_No_x 值。在下面的 SELECT 中，您可以看到我刚刚写了“a.other_no_1 as contact_1_mobile”，但实际上这可能是检索工作号码或 Name2:mobile 号码。这是我第一次向论坛寻求帮助，所以我很抱歉可能没有正确地提出我的问题。感谢您提供的任何帮助。这是我现在的声明：

SELECT final.* 
    FROM (
        SELECT 
        --Name 1 in P1 household
        a.id
        ,a.name1_web_user_id as contact_1_id
        ,a.name1_full_name as contact_1_name
        ,a.other_no_1 as contact_1_mobile (THIS IS MY PROBLEM. "Other_No_1" MAY NOT ACTUALLY BE THE NAME1:MOBILE NUMBER TYPE I NEED. THIS PROBLEM IS THE SAME IN EACH SECTION OF MY STATEMENT.)
        ,a.email as contact_1_email
       
        --Name 2 in P1 household
        ,a.name2_web_user_id as contact_2_id
        ,a.name2_full_name as contact_2_name
        ,a.other_no_2 as contact_2_mobile (PROBLEM: HERE I ACTUALLY NEED TO FIND THE COLUMN THAT CONTAINS THE "Name2:Mobile" NUMBER)
        ,a.EMAIL_2 as contact_2_email
            
    FROM rg_student s left outer join rg_addr a on s.id = a.id
                WHERE  (
                (a.addr_code='P1' AND a.rg_active = 'Y') AND ((a.name1_web_user_id is not null) OR (a.name2_web_user_id is not null))
                            AND a.id in(SELECT id from rg_student where student_group='Student')
                        )
    UNION
    
        SELECT 
        --Name 1 in P2 household
        a.id
        ,a.name1_web_user_id as contact_3_id
        ,a.name1_full_name as contact_3_name
        ,a.other_no_1 as contact_3_mobile (PROBLEM LINE)
        ,a.email as contact_3_email
        
        --Name 2 in P2 household
        ,a.name2_web_user_id as contact_4_id
        ,a.name2_full_name as contact_4_name
        ,a.other_no_2 as contact_4_mobile (PROBLEM LINE)
        ,a.EMAIL_2 as contact_4_email
            
    FROM rg_student s left outer join rg_addr a on s.id = a.id
                WHERE  (
                        (a.addr_code='P2' AND a.rg_active = 'Y') AND ((a.name1_web_user_id is not null) OR (a.name2_web_user_id is not null))
                            AND a.id in(SELECT id from rg_student where student_group='Student')
                        )
         )final
    ORDER BY final.id

Answer 1

只是用例或解码：

case 'Name1:Mobile' 
when Other_No_Type_1 then Other_No_1
when Other_No_Type_2 then Other_No_2
when Other_No_Type_3 then Other_No_3
when Other_No_Type_4 then Other_No_4
end as contact_1_mobile